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Archy [21]
2 years ago
10

Determine whether angle-angle-angle (AAA) is a valid means for establishing triangle congruence. If AAA is a valid criterion, ex

plain why. If it isn’t valid, use GeoGebra to create a counterexample demonstrating that it doesn’t work and give an explanation. If you construct a counterexample, include a screenshot of your work in your answer.
Mathematics
1 answer:
Alexeev081 [22]2 years ago
7 0
Can yu pls send us some picture i cant understand the question and then i will comment an answer thx...
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A report states that the mean yearly salary offer for students graduating with a degree in accounting is $48,734. Suppose that a
DENIUS [597]

Solution :

To claim to be tested is whether "the mean salary is higher than 48,734".

i.e. μ > 48,734

Therefore the null and the alternative hypothesis are

$H_0 : \mu = 48,734$

and $H_1 : \mu > 48,734$

Here, n = 50

$\bar x = 49,830$

s = 3600

We take , α = 0.05

The test statistics t is given by

$t=\frac{\bar x - \mu}{\frac{s}{\sqrt n}}$

$t=\frac{49,830 - 48,734}{\frac{3600}{\sqrt 50}}$

t = 2.15

Now the ">" sign in the $H_1$ sign indicates that the right tailed test

Now degree of freedom, df = n - 1

                                              = 50 - 1

                                              = 49

Therefore, the p value = 0.02

The observed p value is less than α = 0.05, therefore we reject $H_0$. Hence the mean salary that the accounting graduates are offered from the university is more than the average salary of 48,734 dollar.

3 0
3 years ago
Pls help me with this problem:( and I’ll be happy if you write steps for this
andreev551 [17]

Answer:

b/(b+a)

Step-by-step explanation:

(1/a)-(1/b) :[ (b²-a²)/ab²]

first  solve :

common denominator ab

(1/a)-(1/b)  = (b-a)/ab

[b-a/ab] : [(b²-a²)/ab²]

when divide fraction ( division sign turn to (×) and flip the second fraction(reciprocal):

[b-a/ab] × [ab²/ (b²-a²)]

then  simplify : ab²/ab = b

(b-a)×(b/b²-a²)    

factorize : b²-a² = (b-a)(b+a)

(b-a)×(b/(b-a)(b+a))  simplify : (b-a)/b-a = 1

[(b-a)(b)]/[(b-a)(b+a)

b/b+a

4 0
3 years ago
If you have lived for a million seconds, how many birthdays have you had?
Romashka [77]

A million seconds is not that long.  My next birthday is in  1,296,000  seconds
from now, and I have already lived more than  2.3 billion seconds !

(1,000,000 seconds) x (1 day / 86,400 seconds) =

                 11days 13hours 46minutes 40seconds .

It's possible that you might have one birthday within that length of time,
but it's not guaranteed.  It would have to be the RIGHT million seconds.

If that's been your whole life so far ... you are 1 million seconds old ..,
then you have not had your first birthday yet.

7 0
3 years ago
Read 2 more answers
HELP PLZ (NOT VERY HARD)
ikadub [295]

The volume if the top of the salt shaker is 562.5 cubic mm

<u>Step-by-step explanation:</u>

Volume of the top of salt shaker= (1/3) (base area) (height of the pyramid)

= (1/3) (15 x 15) (7.5)

= (1/3) (225) (7.5)

=562.5 cubic mm

The volume if the top of the salt shaker is 562.5 cubic mm.

6 0
3 years ago
How do i find the domain and range of a table
Romashka-Z-Leto [24]

check the picture below.


recall that the x-values are always the domain and the y-values the range.

one can also use the interval notation for domain [-1, 8] and range [4, 13].

7 0
3 years ago
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