Question

From 6 cards bearing the letters a, b, c, d, e, and f, two cards are drawn. Find the probability that at least one of the cards drawn bears a vowel. Note: (a, b) and (b, a) are considered to be different elements in the sample space.
A) 2/15
B) 3/5
C) 5/9

Answer 1

We use the complement rule of probability.
P(at least one vowel) = 1 - P(no vowel)
To solve for P(no vowel) = (4/6)(3/5) = 2/5; since there are 4 consonants out of 6 letters and we take the letters without replacement.

P(at least one vowel) = 1 - 2/5 = 3/5.
The answer is B.

Answer 2

The answer is B just tried it and it is correct. Hope this helps.