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The oxygen consumption of an activated sludge plant is 60 g O2/L.d for the degradation of

Serga [27]

Answer:

sorry di ko alam

Explanation:

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7 0

3 years ago

The step shaft is subjected to a torque of 710 lb·in. If the allowable shear stress for the material is τallow = 12 ksi, determi

Taya2010 [7]

Answer:

The smallest radius at the junction between the cross section that can be used to transmit the torque is 0.167 inches.

Explanation:

Torsional shear stress is determined by the following expression:

$\tau = \frac{T\cdot r}{J}$

Where:

$T$ - Torque, measured in $lbf\cdot in$ .

$r$ - Radius of the cross section, measured in inches.

$J$ - Torsion module, measured in quartic inches.

$\tau$ - Torsional shear stress, measured in pounds per square inch.

The radius of the cross section and torsion module are, respectively:

$r = \frac{D}{2}$

$J = \frac{\pi}{32}\cdot D^{4}$

Where $D$ is the diameter of the cross section, measured in inches.

Then, the shear stress formula is now expanded and simplified as a function of the cross section diameter:

$\tau = T \cdot \frac{D}{\frac{\pi}{16}\cdot D^{4} }$

$\tau = \frac{16\cdot T}{\pi \cdot D^{3}}$

In addition, diameter is cleared:

$D^{3} = \frac{16\cdot T}{\pi \cdot \tau}$

$D = 2\cdot \sqrt[3] {\frac {2\cdot T}{\pi\cdot \tau}}$

If $T = 710\,lb\cdot in$ and $\tau = 12000\,psi$ , then:

$D = \sqrt[3]{\frac{2\cdot (710\,lbf\cdot in)}{\pi \cdot (12000\,psi)} }$

$D \approx 0.335\,in$

$r \approx 0.167\,in$

The smallest radius at the junction between the cross section that can be used to transmit the torque is 0.167 inches.

4 0

4 years ago

1. Get the trDFgrouped data starting from the May heavy day counts to the August heavy counts

Ivenika [448]

Hey I need a time in your life to help nnuum

7 0

3 years ago

Relationship between civil engineering and geology

natka813 [3]

Answer:

Geological and civil engineers sometimes work together, but have very different responsibilities. While geological engineers study the earth's inner and outer surface to evaluate potential mining and infrastructure construction sites, civil engineers design the infrastructure to be built.

5 0

3 years ago

Calculate the Lee for the same wing if we increase the span to 0.245 m. By increasing the span we also increase the glider weigh

alexira [117]

Answer:

0.21

Explanation:

This would have been a fairly easy one, except for that the first part of the question is missing, and as such, I'd assume a value.

We need to use chord, so, I'm assuming the length of the chord to be 0.045 m

The Area is given by the formula

Area = span * chord

Area = 0.245 * 0.045

Area = 0.011 m²

This area gotten, is what we then divide the glider weight by to get our answer.

Lee = area / weight

Lee = 0.011 / 0.0523

Lee = 0.21

Therefore, using the values of the chord I'd assumed, the Lee of the same wing is 0.21

8 0

3 years ago

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