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expeople1 [14]
4 years ago
11

Technician A says the final drive assembly always has a gear ratio of 1:1. Technician B says the final drive assembly provides f

urther gear reduction between the transmission and the drive wheels. Who is correct?
Engineering
1 answer:
Olenka [21]4 years ago
5 0

Answer:

Technician B only is correct

Explanation:

The last stage of gears found between the vehicle transmission system and the wheels is the final drive ratio. The function of the final drive gear assembly is to enable a gear reduction control stage to reduce the rotation per minute and increase the wheel torque, such that the vehicle performance can be adjusted and the final gear ratio can be between 3:1 and 4.5:1 not 1:1

Therefore, technician B only is correct

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A long aluminum wire of diameter 3 mm is extruded at a temperature of 280°C. The wire is subjected to cross air flow at 20°C at
Musya8 [376]

Answer:

Explanation:

Given:

Diameter of aluminum wire, D = 3mm

Temperature of aluminum wire, T_{s}=280^{o}C

Temperature of air, T_{\infinity}=20^{o}C

Velocity of air flow V=5.5m/s

The film temperature is determined as:

T_{f}=\frac{T_{s}-T_{\infinity}}{2}\\\\=\frac{280-20}{2}\\\\=150^{o}C

from the table, properties of air at 1 atm pressure

At T_{f}=150^{o}C

Thermal conductivity, K = 0.03443 W/m^oC; kinematic viscosity v=2.860 \times 10^{-5} m^2/s; Prandtl number Pr=0.70275

The reynolds number for the flow is determined as:

Re=\frac{VD}{v}\\\\=\frac{5.5 \times(3\times10^{-3})}{2.86\times10^{-5}}\\\\=576.92

sice the obtained reynolds number is less than 2\times10^5, the flow is said to be laminar.

The nusselt number is determined from the relation given by:

Nu_{cyl}= 0.3 + \frac{0.62Re^{0.5}Pr^{\frac{1}{3}}}{[1+(\frac{0.4}{Pr})^{\frac{2}{3}}]^{\frac{1}{4}}}[1+(\frac{Re}{282000})^{\frac{5}{8}}]^{\frac{4}{5}}

Nu_{cyl}= 0.3 + \frac{0.62(576.92)^{0.5}(0.70275)^{\frac{1}{3}}}{[1+(\frac{0.4}{(0.70275)})^{\frac{2}{3}}]^{\frac{1}{4}}}[1+(\frac{576.92}{282000})^{\frac{5}{8}}]^{\frac{4}{5}}\\\\=12.11

The covective heat transfer coefficient is given by:

Nu_{cyl}=\frac{hD}{k}

Rewrite and solve for h

h=\frac{Nu_{cyl}\timesk}{D}\\\\=\frac{12.11\times0.03443}{3\times10^{-3}}\\\\=138.98 W/m^{2}.K

The rate of heat transfer from the wire to the air per meter length is determined from the equation is given by:

Q=hA_{s}(T_{s}-T{\infin})\\\\=h\times(\pi\timesDL)\times(T_{s}-T{\infinity})\\\\=138.92\times(\pi\times3\times10^{-3}\times1)\times(280-20)\\\\=340.42W/m

The rate of heat transfer from the wire to the air per meter length is Q=340.42W/m

6 0
3 years ago
A defective crankshaft position sensor is a common cause of a no-start condition.
ohaa [14]

Answer:

Switching on and off

Explanation:

No starters are often caused by a faulty crankshaft actuator. The signals from this transmitter is sent to the ignition module, which turns in and out of the ignition system. If you already have an RPM sign, it's possible that a faulty ignition unit or PCM isn't turning the coils on and off. Along with button on and the motor cranking, testing for volts at the contacts with a voltmeter.

3 0
3 years ago
A well-insulated rigid tank contains 5 kg of a saturated liquid–vapor mixture of water at 200 kPa. Initially, three-quarters of
vlabodo [156]

Answer:

S_{gen} = 18.519\,\frac{kJ}{K}

Explanation:

Given that rigid tank is a closed system, the following model is constructed after the First Law of Thermodynamics:

W_{heater} + U_{sys,1} - U_{sys,2} = 0

W_{heater} = U_{sys,2} - U_{sys,1}

W_{heater} = m\cdot (u_{2}-u_{1})

The entropy generation inside the rigid tank is determined by appropriate application of the Second Law of Thermodynamics:

S_{sys,1} - S_{sys,2} + S_{gen} = 0

S_{gen} = S_{sys,2} - S_{sys,1}

S_{gen} = m\cdot (s_{2}-s_{1})

The properties of the steam are obtained from steam tables:

Intial State

P = 200\,kPa

T = 120.21\,^{\textdegree}C

\nu = 0.2222\,\frac{m^{3}}{kg}

u = 1010.7\,\frac{kJ}{kg}

s = 2.9294\,\frac{kJ}{kg\cdot K}

x = 0.25

Final State

P = 869.567\,kPa

T = 173.88\,^{\textdegree} C

\nu = 0.2222\,\frac{m^{3}}{kg}

u = 2578.6\,\frac{kJ}{kg}

s = 6.6332\,\frac{kJ}{kg\cdot K}

x = 1.00

The entropy change of the steam during the process is:

S_{gen} = (5\,kg)\cdot \left(6.6332\,\frac{kJ}{kg\cdot K} - 2.9294\,\frac{kJ}{kg\cdot K} \right)

S_{gen} = 18.519\,\frac{kJ}{K}

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4 years ago
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Answer:

c from transmitter to a receiver

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Answer:

Dam they be thinking we racist

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