Answer:
Correct answer: E total = 2,800 J
Explanation:
Given:
m = 4 kg the mass of the object
V = 20 m/s the speed (velocity) of the object
H = 50 m the height of the object above the surface
E total = ? J
The total energy of an object is equal to the sum of potential and kinetic energy
E total = Ep + Ek
Ep = m g H we take g = 10 m/s²
Ep = 4 · 10 · 50 = 2,000 J
Ek = m V² / 2
Ek = 4 · 20² / 2 = 2 · 400 = 800 J
E total = 2,000 + 800 = 2,800 J
E total = 2,800 J
God is with you!!!
Answer:
The total distance, side to side, that the top of the building moves during such an oscillation = 31 cm
Explanation:
Let the total side to side motion be 2A. Where A is maximum acceleration.
Now, we know know that equation for maximum acceleration is;
A = α(max) / [(2πf)^(2)]
So 2A = 2[α(max) / [(2πf)^(2)] ]
α(max) = (0.025 x 9.81) while frequency(f) from the question is 0.2Hz.
Therefore 2A = 2 [(0.025 x 9.81) / [((2π(0.2)) ^(2)] ] = 2( 0.245 / 1.58) = 0.31m or 31cm
Answer:
The kite string is 
feet long.
Explanation:
Use the Pythagorean Theorem, which is 
.
Here the question is asking for 
, which would be the hypotenuse, or the longest side of the triangle.
So the 
would be 
, and the 
would be 
.
Plug those values into the formula, and that would get 
.
Now, solve for 
, which would equal 
.
That means we would have to solve for 
.
Square root both sides of the equation, getting 
.
Solve for 
, which would get us .
Hence, the answer to this would question would be .
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Answer:
The capacitor will charge
Explanation:
When the capacitor is connected to the circuit containing the battery and the resistor, charges (electrons) will start flowing through the circuit, pushed by the electromotive force produced by the battery. In particular:
- electrons will flow from the negative terminal of the battery to one plate of the capacitor
- electrons will flow from the other plate of the capacitor to the positive terminal fo the battery
(It's important to keep in mind that the electrons never cross the gap between the plates of the capacitor.)
Therefore, negative charge will accumulate on one plate of the capacitor and positive charge will accumulate on the other plate: and so, there will be an increasing potential difference across the plates of the capacitor. Due to this increasing potential difference, it will become more and more difficult for the battery to "push" electrons on the negative plate (and to remove them from the other plates), so the current in the circuit will keep decreasing.
The process stops when the potential difference across the gap of the capacitor is equal to the e.m.f. of the battery: at this point, there is no more current in the circuit, and the capacitor is said to be fully charged.
