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Leni [432]
3 years ago
7

Wood, plastic, rubber and air are good insulators because A. they conduct charge. B. charge flows easily. C. they don’t have fre

e electrons. D. they have low resistance.
Physics
1 answer:
Julli [10]3 years ago
6 0
C. They don't have free electrons.
The only things capable of conducting a charge are things that have charged particles in them that are free to move, e.g free electrons, free positions, or dissociated ions
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an ore is a naturally occurring solid material from which a metal or valuable mineral can be profitably extracted.

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Frictional forces acting on an object are often converted into __________ energy, which causes the temperature of the object to
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Heat energy. Friction causes heat build-up.
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active and passive secruity measures are employed to identify, detect, classify and analyze possible threats inside of which zon
Juli2301 [7.4K]

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Assessment zone

Explanation:

It is the assessment zone in various security zones where active and passive security measures are employed to identify, detect, classify and analyze possible threats inside the assessment zones.

8 0
3 years ago
A ball bearing took 20.9ˍs to fall when dropped from a helicopter. From what height was the ball bearing dropped?
mr_godi [17]

\boxed{ \bf{Given : }}

  • Time taken by a ball bearing = 20.9 seconds

  • Initial velocity,u = 0 m/s [ Body starts from rest ]

  • Acceleration due to gravity,g = 9.8 m/s²

\boxed{ \bf{To \:  be \:  calculated :  }}

From what height was the ball bearing dropped?

\boxed{ \bf{Solution : }}

By using second equation for freely falling body, we get:

\sf{h = ut +  \frac{1}{2} gt {}^{2} }

Substituting the values..

\sf\rightarrow \: h = 0 \times 20.9 +  \dfrac{1}{  \cancel{2}}  \times   \cancel{9.8} \times 20.9

\sf \rightarrow \: h = 0 + 4.9 \times 20.9

\sf \rightarrow \: 102.41 \: m \: (approx)

\bf \therefore \: Height \:   is \:  102.41 \: m

8 0
3 years ago
A block of mass m = 2.20 kg slides down a 30.0° incline which is 3.60 m high. At the bottom, it strikes a block of mass M = 6.80
Bogdan [553]

Answer:

(a) The speed of the lighter block is v_{2x} = 3.7~m/s.

    The speed of the heavier block is v_{3x} = 3.55~m/s.

(b) The smaller block goes up to 0.69 m.

Explanation:

We will divide this question into three parts: Part A is for the smaller mass from the top of the incline to the collision. Part B is the collision. And Part C is for the smaller mass from the bottom to the highest point it can achieve.

In order to solve this question, I will assume that the smaller mass is initially at rest.

Part A:

We will use conservation of energy.

K_1 + U_1 = K_2 + U_2\\0 + mgh = \frac{1}{2}mv_1^2  + 0\\(2.2)(9.8)(3.6) = \frac{1}{2}(2.2)v_1^2\\v_1 = 8.4 ~m/s

This is the speed of the smaller mass just before the collision. The velocity of the mass is directed 30° above horizontal, since the mass is sliding down the incline.

Part B:

Momentum is a vector identity, so the x- and y-components of momentum are to be investigated separately. Since the collision occurs at the horizontal surface, only the x-component of momentum is conserved.

P_1 = P_2\\mv_{1x} = mv_{2x} + Mv_{3x}\\(2.2)(8.4\cos(30^\circ)) = (2.2)v_{2x} + (6.8)v_{3x}\\16 = 2.2v_{2x} + 6.8v_{3x}

During the collision kinetic energy is also conserved. Since kinetic energy is a scalar quantity, we don't have to separate its components.

K_{initial} = K_{final}\\\frac{1}{2}mv_1^2 = \frac{1}{2}mv_{2}^2 + \frac{1}{2}Mv_{3x}^2\\(2.2)(8.4)^2 = (2.2)v_{2}^2 + (6.8)v_{3x}^2\\155.23 = 2.2v_{2}^2 + 6.8v_{3x}^2

The following relation will be used when combining the two equations:

v_{2x} = v_2\cos{30^\circ}

The following equation is useful for combining the two equations:

v_{3x} = \frac{2m}{(m+M)}v_{1x} = \frac{2(2.2)}{(2.2 + 6.8)}(8.4\cos(30^\circ)) = 3.55~m/s

Therefore from the first equation,

16 = 2.2v_{2x} + 6.8v_{3x} = 2.2v_{2x} + 6.8(3.55) \\v_{2x} = -3.7~m/s

Part C:

We will again use the conservation of energy to find the highest point that the mass can go:

K_1 + U_1 = K_2 + U_2\\\frac{1}{2}mv_{2x}^2 + 0 = 0 + mgH\\\frac{1}{2}(2.2)(-3.7)^2 = (2.2)(9.8)H\\H = 0.69 ~m

4 0
4 years ago
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