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Sergeeva-Olga [200]
3 years ago
15

Knowledge and skills learned through socialization are an example of

Physics
1 answer:
ziro4ka [17]3 years ago
3 0

Answer:

I think no.2 the answer

Because socialization and social resources are both for me

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Latitude and longitude picture.​
TiliK225 [7]

Answer:

where? please comment it

Explanation:

7 0
2 years ago
A 2400W electric toaster is connected to a standard 120 V wall outlet. A family
jolli1 [7]

Answer:

1)  energy = 15.6 kWh,  2)    total_cost = $ 2.03

Explanation:

1) The energy dissipated is the product of the power and the time of use In a month it was used t = 6.5 h and the power of the toaster is

P = 2400 W = 2,400 kW

       energy = P  t

       energy = 2,400  6.5

        energy = 15.6  kWh

using rounding to a decimal

        energy = 15.6 kWh

2) The cost of energy is unit_cost = $ 0.13 / kWh

so the total cost

         total_cost = energy    unit_cost

         total_cost = 15.6   0.13

         total_cost = $ 2.028  

rounding to two decimal places

         total_cost = $ 2.03

5 0
2 years ago
5. Which of these is necessary for electricity to flow?
CaHeK987 [17]

Answer:

the circuit must be closed

Explanation:

4 0
2 years ago
Read 2 more answers
A wheel rotates about a fixed axis with a constant angular acceleration of 3.3 rad/s2. The diameter of the wheel is 21 cm. What
AleksandrR [38]

Answer:

The the linear speed (in m/s) of a point on the rim of this wheel at an instant=0.418 m/s

Explanation:

We are given that

Angular acceleration, \alpha=3.3 rad/s^2

Diameter of the wheel, d=21 cm

Radius of wheel, r=\frac{d}{2}=\frac{21}{2} cm

Radius of wheel, r=\frac{21\times 10^{-2}}{2} m

1m=100 cm

Magnitude of total linear acceleration, a=1.7 m/s^2

We have to find the linear speed  of a  at an instant when that point has a total linear acceleration with a magnitude of 1.7 m/s2.

Tangential acceleration,a_t=\alpha r

a_t=3.3\times \frac{21\times 10^{-2}}{2}

a_t=34.65\times 10^{-2}m/s^2

Radial acceleration,a_r=\frac{v^2}{r}

We know that

a=\sqrt{a^2_t+a^2_r}

Using the formula

1.7=\sqrt{(34.65\times 10^{-2})^2+(\frac{v^2}{r})^2}

Squaring on both sides

we get

2.89=1200.6225\times 10^{-4}+\frac{v^4}{r^2}

\frac{v^4}{r^2}=2.89-1200.6225\times 10^{-4}

v^4=r^2\times 2.7699

v^4=(10.5\times 10^{-2})^2\times 2.7699

v=((10.5\times 10^{-2})^2\times 2.7699)^{\frac{1}{4}}

v=0.418 m/s

Hence, the the linear speed (in m/s) of a point on the rim of this wheel at an instant=0.418 m/s

6 0
2 years ago
9As a student walks downhill at constant speed, his gravitational potential energy
Minchanka [31]

Answer:

jfsfjsjfsjfsjgsjfskra

Explanation:

sgnsfnNCzgnzncxmhshdgNdfjBFzktajfskgskgzngzngzgnzngzngzfNFzngzngznfzngzngzngzng

4)sfjskgdgxgkzhldlhdhkdkhdgkdkgzgksfnsksgkskfsufsursjfsjrsjfBFHDahdJFzbfzkgzndcxdnvxekvxlhecihckheclheclhexhiecohceoheclhecohecohecohceohceohecohceihcelhevlhecohcehlcegicgei.

4 0
3 years ago
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