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mel-nik [20]
3 years ago
13

3.2249030993 round to the nearest hundreth

Mathematics
2 answers:
Nitella [24]3 years ago
7 0

Answer:

3.22

Step-by-step explanation:

I'm not the best at explaining things so theres the anwser at least.

Hope I helped.

SJ

anyanavicka [17]3 years ago
5 0

Answer:

3.23

Step-by-step explanation:

9 is up to 5, so it's turned into 1 then take it to 4. It becomes 5, and it's up to 5, it's turned into 1 then take it to 2. It will become 3.

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I'm giving 50 POINTS and I mark BRAILIEST the question is provided. in the picture Please include ALL WORK and simplify. TYYY ❤️
IrinaVladis [17]

The answer is 4

The answers is four because 10/3(aka 3 1/3) +2/3=(10 ×3)+ (2×3)/3×3=36/9= 36 ÷ 9/9÷9=4

so the answer is four

4 0
3 years ago
1.Simplify 5 to the 5th over 5 to the 8th.
timurjin [86]
Q1. The answer is <span>1 over 5 to the 3rd power.

</span>5 to the 5th is 5⁵
5 to the 8th is 5⁸
5 to the 5th over 5 to the 8th is \frac{ 5^{5} }{ 5^{8} }
To simplify, we will use two rules: 
\frac{ x^{a}}{ x^{b} } = x^{a-b} \\ x^{-a} = \frac{1}{ x^{a}}
Therefore:
\frac{ 5^{5} }{ 5^{8} } = 5^{5-8} =5^{-3}= \frac{1}{5^{3}}
\frac{1}{5^{3}} is the same as 1 over 5 to the 3rd power.


Q2. The answer is <span>(53)−4.

The exponents are multiplied when are expressed in the form:
</span>(x^{a}) ^{b}= x^{a*b}
So, (5^{3} )^{-4}=5^{3*(-4)}=5^{-12}

Other choices are incorrect:
<span>one third to the 4th times one third to the 7th is </span>( \frac{1}{3} )^{4} *( \frac{1}{3} )^{7}=( \frac{1}{3} )^{4+7}
3 to the 7th over 3 to the 15th is \frac{ 3^{7} }{3^{15}} =3^{7-15}
<span>45 ⋅ 42 is </span>4^{5}* 4^{2} =  4^{5+2}
3 0
3 years ago
Read 2 more answers
Find 3 consecutive square numbers whose sum is 149​
poizon [28]

Answer:

36, 49, 64

Step-by-step explanation:

6 squared, 7 squared, 8 squared makes 149

6 0
2 years ago
Activity 2
Vsevolod [243]
The unknown is 2% and sorry
7 0
3 years ago
Rajan needs 1 liter of 15% hydrochloric acid solution for an experiment. He checks his storage cabinet, but he only has a 5-lite
yarga [219]

Answer:

<em>Rajan must use </em><em>0.75</em><em> liters of 5% hydrochloric acid solution and </em><em>0.25</em><em> liters of 45% hydrochloric acid solution.</em>

Step-by-step explanation:

Let us assume that, x liters of the 5% hydrochloric acid and y liters of the 45% hydrochloric acid solutions are combined.

As Rajan need total of 1 liter of solution, so

x+y=1

i.e x=1-y --------------------1

As Rajan needs 5% hydrochloric acid and 45% hydrochloric acid to make a 1 liter batch of 15% hydrochloric acid, hence acid content of the mixture of two acids will be same as of the final one, so

0.05x+0.45y=1\times 0.15

i.e 5x+45y=15 -------------2

Putting value of x from equation 1 in equation 2,

\Rightarrow 5(1-y)+45y=15

\Rightarrow 5-5y+45y=15

\Rightarrow 5+40y=15

\Rightarrow 40y=15-5=10

\Rightarrow y=0.25

Putting the value of y in equation 1,

x=1-0.25=0.75

Therefore, Rajan must use 0.75 liters of 5% hydrochloric acid solution and 0.25 liters of 45% hydrochloric acid solution.

5 0
3 years ago
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