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2 years ago

For which of the following situations would a sample be used versus a population? Select all that apply.

Mathematics

1 answer:

muminat2 years ago

8 0

Answer:

Step-by-step explanation:

A biologist is interested in the average wingspan of hawks in the United States.

and

A researcher is interested in the average birth weight of newborn babies born in the United States.

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4b+24=7b-8 Please show steps

LUCKY_DIMON [66]

4b+24=7b-8
32=3b
b=32/3
hope this helps!

5 0

3 years ago

Complete the following statement given: QXR=NYC a.QX= ? b. Y=?

AfilCa [17]

Answer:

Step-by-step explanation:

3 0

3 years ago

A triangle contains angles mesuring 28 degrees and 37 degrees. How many degrees is the third angle?

Orlov [11]

Answer:

115°

Step-by-step explanation:

We know that:

Angles ∠A and ∠B are 28° and 37°.

We don't know:

Angle ∠C's angle

So, we do this:

Add the 180°
Solve the equation 180 - 28 - 37

Solve:

180 - 28
= 152 - 37
= 115.

Angle ∠C is 115°.

8 0

2 years ago

Ethan throws a ball into the air from a cliff that is 152.4 m high with an initial velocity of 4 m/s. How long does it take for

Dmitry_Shevchenko [17]

38.1 seconds I believe simply divide 4m/s into 152.4 m and you will have 38.1 seconds

8 0

3 years ago

Read 2 more answers

Miriam is picking out some movies to rent, and she is primarily interested in comedies and foreign films. She has narrowed down

Keith_Richards [23]

Answer:

There are 795 combinations.

Step-by-step explanation:

The number of ways or combinations in which we can select k element from a group of n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, if Miriam want to choose 3 movies with at least two comedies, she have two options: Choose 2 comedies and 1 foreign film or choose 3 comedies.

Then, the number of combinations for every case are:

1. Choose 2 Comedies from the 10 and choose 1 foreign film from 15. This is calculated as:

$10C2*15C1=\frac{10!}{2!(10-8)!}*\frac{15}{1!(15-14)!}$

$10C2*15C1=675$

2. Choose 3 Comedies from the 10. This is calculated as:

$10C3=\frac{10!}{3!(10-3)!}=120$

Therefore, there are 795 combinations and it is calculated as:

675 + 120 = 795

8 0

3 years ago