Set up an algebraic equation: b=cost of ball
1.10=1+b+b
1.10=1+2b
subtract 1 from both sides
.10=2b
divide by 2 on both sides
ball=5 cents
Answer:
19 seconds.
Step-by-step explanation:
Given that the clock was exactly on time at 7am, and at 1pm the clock was 228 seconds late, to determine, at that rate, how slow was the clock half an hour, the following calculation must be performed:
1 PM = 13:00
13 - 7 = 6
228/6 = 38
38/2 = 19
Thus, every half hour the clock is delayed 19 seconds.
It will take 6 years for that to happen.
You can find this by setting Nichole's age as x and Sophie's age as x + 28 since she will always be 28 years older.
Now we are looking for a time that Sophie's age is equal to 2 less than 6 times Nichole's age. So we can set up the below equation.
6(x) - 2 = x + 28
6x - 2 = x + 28
5x - 2 = 28
5x = 30
x = 6
This let's us know that it needs to be when Nichole is 6, which is 6 years in the future.
Got a picture for this question?
Haven't been taught this; but from what I searched up; I think the postulate for proving these shapes' congruence is Hypotenuse/Leg. I have no exact idea however. Correct me if I'm wrong :/