The ordered pair maximizes the objective function p = 3x + 8y will be (5, 6) .Option C is correct.
<h3>What is the objective function?</h3>
The objective function is simply an equation that represents the goal production capability that relates to maximizing profits in relation to manufacturing.
On putting the values we will get the values one by one. We get;
1. (0, 0)
2. (2,7)
3. (5,6)
4. (8,1)
The maximum value obtained from the 63. Obtained from option C. The ordered pair maximizes the objective function p = 3x + 8y will be (5, 6)
Hence option C is correct.
To learn more about the objective function refer to the link;
brainly.com/question/15830007
The answer is (1/2)xe^(2x) - (1/4)e^(2x) + C
Solution:
Since our given integrand is the product of the functions x and e^(2x), we can use the formula for integration by parts by choosing
u = x
dv/dx = e^(2x)
By differentiating u, we get
du/dx= 1
By integrating dv/dx= e^(2x), we have
v =∫e^(2x) dx = (1/2)e^(2x)
Then we substitute these values to the integration by parts formula:
∫ u(dv/dx) dx = uv −∫ v(du/dx) dx
∫ x e^(2x) dx = (x) (1/2)e^(2x) - ∫ ((1/2) e^(2x)) (1) dx
= (1/2)xe^(2x) - (1/2)∫[e^(2x)] dx
= (1/2)xe^(2x) - (1/2) (1/2)e^(2x) + C
where c is the constant of integration.
Therefore,
∫ x e^(2x) dx = (1/2)xe^(2x) - (1/4)e^(2x) + C
I think it would be the Multiplication property of equality
lol
Step-by-step explanation:
If you do order of operations, you divide 6 and 2 getting 3. Add 42 and 3. 45 is the answer.
