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iren [92.7K]
2 years ago
6

What are the rules of trichotomy???​

Mathematics
2 answers:
Finger [1]2 years ago
8 0

Answer:

Step-by-step explanation:

The answer is in the attachment.

Besides this, there are more rules of trichotomy.

ivann1987 [24]2 years ago
8 0

Answer:

Let us consider any two numbers 6 and 9 then we have the relation.

\gray{ \frak{9 > 6 \:  \:  \: or \:  \:  \: 6 < 9}}

<em><u>Rule </u></em><em><u>1</u></em><em><u>.</u></em>

Adding 2 on both sides then;

\frak{ \gray{9 + 2 > 6 + 2 \:  \:  \: or \:  \:  \: 6 + 2 < 9 + 2}}

\frak{ \gray{ \therefore \: 11 > 8 \:  \:  \: or \:  \:  \: 8 < 11}}

Both are true for addition.

Thus,<u>when </u><u>equal</u><u> </u><u>number</u><u> is</u><u> </u><u>added</u><u> to</u><u> </u><u>both </u><u>sides</u><u> of</u><u> </u><u>trichotomy</u><u> </u><u>symbol,</u><u>the </u><u>symbol </u><u>remains</u><u> the</u><u> same</u><u>.</u>

<em><u>Rule </u></em><em><u>2</u></em><em><u>.</u></em>

Subtracting 2 on the both sides then,

\frak{ \gray{9 - 2 > 6 - 2 \:  \:  \: or \:  \:  \: 6 - 2 < 9 - 2}}

\frak{ \gray{\therefore \:  7 > 4 \:  \:  \: or \:  \:  \: 4 < 7}}

Both are true for subtraction.

Thus,<u>when </u><u>equal</u><u> number</u><u> is</u><u> </u><u>subtracted </u><u>to </u><u>both</u><u> sides</u><u> of</u><u> trichotomy</u><u> symbol</u><u>,</u><u>the </u><u>symbol</u><u> remains</u><u> the</u><u> same</u><u>.</u>

<em><u>Rule </u></em><em><u>3</u></em><em><u>.</u></em>

Multiplying both sides by 2 then,

\frak{ \gray{9 \times 2 > 6 \times 2 \:  \:  \: or \:  \:  \: 6 \times 2 < 9 \times 2}}

\frak{ \gray{ \therefore \: 18 > 12 \:  \:  \: or \:  \:  \: 12 < 18}}

Both are true for multiplication by positive numbers.

But if we multiplied by -2 then there will be,

\frak{ \gray{ - 18 >  - 12 \:  \:  \: or \:  \:  \:  - 12 <  - 18}}

These are not true.

To be true,there must be:

\frak{ \gray{ - 18 <  - 12 \:  \:  \: and \:  \:  \:  - 12 >  - 18}}

Thus<u>,</u><u>when </u><u>both</u><u> sides</u><u> of</u><u> trichotomy</u><u> symbol</u><u> </u><u>are </u><u>multiplied </u><u>by</u><u> </u><u>equal</u><u> </u><u>positive</u><u> </u><u>number </u><u>then </u><u>the </u><u>symbol</u><u> </u><u>remains</u><u> the</u><u> </u><u>same.When </u><u>both </u><u>sides</u><u> of</u><u> trichotomy</u><u> </u><u>symbols </u><u>are </u><u>multiplied</u><u> </u><u>by </u><u>equal</u><u> </u><u>negative</u><u> </u><u>numbers </u><u>then </u><u>the </u><u>symbol</u><u> </u><u>changes</u><u> </u>as follows:

'<' Changes to'>' and '>' Changes to'<'.

Similarly check for division then get the same result as in multiplication.

Thus<u>,</u><u>when </u><u>both</u><u> sides</u><u> of</u><u> trichotomy</u><u> symbol</u><u> </u><u>are </u><u>divided</u><u> by</u><u> </u><u>an </u><u>equal</u><u> </u><u>positive</u><u> number</u><u>,</u><u> the</u><u> </u><u>symbol</u><u> </u><u>remains</u><u> the</u><u> </u><u>same.When </u><u>both</u><u> sides</u><u> of</u><u> trichotomy</u><u> symbol</u><u> are</u><u> divided</u><u> by</u><u> </u><u>an </u><u>equal</u><u> </u><u>negative</u><u> </u><u>number,</u><u>the </u><u>symbol </u><u>'</u><u><</u><u>'</u><u> </u><u>is </u><u>changed</u><u> to</u><u>'</u><u>></u><u>'</u><u> </u><u>or </u><u>'</u><u>></u><u>'</u><u> </u><u>is </u><u>changed</u><u> to</u><u>'</u><u><</u><u>'</u><u>.</u>

\boxed{\frak{\gray{BrainlyFairy}}}

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