Answer:
A .cos(x)<1
Step-by-step explanation:
According to the first inequality
cos(x)<1
x < arccos 1
x<0
This therefore does not have a solution within the range 0 ≤ x ≤ 2pi
x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.
For the second option
.cos(x/2)<1
x/2< arccos1
x/2<0
x<0
This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.
For the inequality csc(x)<1
1/sin(x) < 1
1< sin(x)
sinx>1
x>arcsin1
x>90°
x>π/2
This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values
For the inequality csc(x/2)<1
1/sin(x/2) < 1
1< sin(x/2)
sin(x/2)> 1
x/2 > arcsin1
X/2 > 90°
x>180°
x>π
This value of x also has a solution within the range.
Therefore option A is the only inequality that does not have a solution with the range.
Answer:
23: 21
25: 1
Step-by-step explanation:
<u>Question 23</u>:
1) add the whole numbers together: 15+5=20
2)To add fractions, both need to have the same denominator. Find a number that is a multiple of both denominators (in this case 55)
→ 
(multiply the numerator and denominator by 5)
→ 
(multiply the numerator and denominator by 11)
3) add the fractions together
+ = 
(add the numerators)
4) Turn the improper fraction into a mixed number
Divide 78 by 55. You'll get a whole number and a remainder. The remainder is the new numerator: In this case 55 enters 78 once with a remainder of 23. Therefore:
1
5) Add the whole numbers together to get the final answer:
20+1= 21
Answer: 21
<u>Question 25</u>:
Follow the above steps but subtract instead of adding
It should be 11, yes. Sounds like simple subtraction
12 x 5 = 60 so The cost of 60 oranges is $6.00.
