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igor_vitrenko [27]
2 years ago
6

Place the following from smallest to largest

Chemistry
2 answers:
gavmur [86]2 years ago
8 0

Answer:

Range

Explanation:

glucose molecule

Proton

heumatom

electron

carbon-14 atom

olga_2 [115]2 years ago
3 0

Answer:

i think electron but not sure ans

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NaOH(aq) + MgSO4(aq) →
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The half life for the first order conversion of A to B is 56.6 hours. How long does it take for the concentration of A to decrea
sveta [45]

Answer:

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

Explanation:

A → B

Initial concentration of the reactant = x

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Time taken by the sample, t = ?

Formula used :

A=A_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

where,

A_o = initial concentration of reactant

A = concentration of reactant left after the time, (t)

t_{\frac{1}{2}} = half life of the first order conversion  = 56.6 hour

\lambda = rate constant

A=A_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}

Now put all the given values in this formula, we get

0.1x=x\times e^{-(\frac{0.693}{56.6 hour})\times t}

t = 188.06 hour

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