Answer:
130 g of sucrose
Explanation:
Boiling point elevation formula → ΔT = Kb . m
ΔT = Boiling T° solution - Boiling T° pure solvent → 0.39°C
0.39°C = 0.513°C/m . M
m = 0.760 mol/kg → molality = moles of solute / 1kg of solvent
Let's determine the moles of solute → molality . kg
0.760 mol/kg. 0.5 kg = 0.380 moles
If we convert the moles to mass, we'll get the answer
0.380 mol . 342.30 g/mol = 130g
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The conditions of temperature and pressure in which a gas least soluble in water is low pressure and high temperature.
<h3>What is Henry Law?</h3>
The amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid, according to Henry's law.
From this law it is clear that:
- As the pressure of the gas increases solubility of the gas on the liquid also increases.
But if the temperature of the liquid decreases then the solubility of the gas also increases.
Hence at low pressure and high temperature, gas is least soluble.
To know more about solubility of gas, visit the below link:
brainly.com/question/14747303
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