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mel-nik [20]
4 years ago
6

Base your answer on the information below and your knowledge of chemistry. Methanol can be manufactured by a reaction that is re

versible. In the reaction, carbon monoxide gas and hydrogen gas react using a catalyst. The equation below represents this system at equilibrium. CO(g) 2H2(g) CH3OH(g) energy. Explain, in terms of collision theory, why increasing the concentration of H2(g) in this system will increase the concentration of CH3OH(g).
Chemistry
1 answer:
Rudiy274 years ago
3 0

Explanation:

For the given reaction:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

CO(g)+2H_2(g)\rightarrow CH_3OH(g)

Rate=k[CO]^x[H_2]^y

where x and y are order wrt to CO and H_2

According to collision theory , the molecules must collide for a reaction to take place. According to collision theory , the rate of a reaction is proportional to rate of collision of reactants.

Thus with an increase in concentration of reactants , the rate of reaction also increases. This is because if the concentration of reactants increases , the chances of collision between molecules also increases and thus more products wil be formed which in turn increases the rate of reaction.

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4 0
2 years ago
Potassium is isotopic and has RAM of 39.5 work out the percentage abundance of each isotope in a given sample of potassium which
Troyanec [42]

Yo sup??

Let the percentage of K-39 be x

then the percentage of K-40 is 100-(x+0.01)

We know that the net weight should be 39.5. Therefore we can say

(39*x+40*(100-(x+0.01))+38*0.01)/100=39.5  

(since we are taking it in percent)

39*x+40*(100-(x+0.01))+38*0.01=3950

39x+4000-40x-0.4+0.38=3950

2x=49.98

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3 0
3 years ago
Read the following chemical equations.
lora16 [44]

This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:

Reaction 1: 2K⁺I⁻ + H₂⁺O₂⁻  ⇒2K⁺O⁻²H⁺ + I₂⁰

Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻

Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.

In such a way, the correct choice is C.

Learn more:

  • (Redox reactions) brainly.com/question/13978139

8 0
2 years ago
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Answer:

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Plug in all the values in the above equation:

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or, mmol of CH_{3}COO^{-} = 37

So 37 mmol of acetate need to add to this solution.

3 0
3 years ago
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