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Lemur [1.5K]
3 years ago
10

F(x)=x+7 if you know the domain is {-9,-3} then the range must be?

Mathematics
1 answer:
RSB [31]3 years ago
7 0
Domain is the set of x-values and range is the set of images f(x).

x           F(x) = x + 7

-9         -9 + 7 = -2

-8         -8 + 7 = -1

-7          -7 + 7 = 0

-6           -6 + 7 = 1

-5           -5 + 7 = 2

-4           -4 + 7 = 3

-3           -3 + 7 = 4

So the range is {-2,4} <------ answer
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Calculate the slope of a line that goes through the points: (5, 7) &amp; (2, 7). Leave your solution as a simplified (improper)
Fiesta28 [93]

Answer:

0

Step-by-step explanation:

m=(y2-y1)/x2-x1), if m is slope and the 2 points are (x1, y1), (x2, y2).

m=(7-7)/(2-5)

m=0/-3

m=0

also, you don't need to know this but if a line has a slope of zero it's a horizontal line

5 0
2 years ago
900 + 50 + 4 + 0.7<br> Please help me
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Answer:

954.7

Step-by-step explanation:

Hope that this is helpful.

Have a nice day.

4 0
2 years ago
The time it takes a runner to complete a race is inversely related to the speed of the runner if a runner can complete a race in
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3 years ago
Football team play $28 per jersey. They bought 16 jerseys. How much money did the team spend on jerseys
yaroslaw [1]
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5 0
3 years ago
The National Cancer Institute estimates that 3.65% of women in their 60s get breast cancer. A mammogram can typically identify c
masha68 [24]

Answer:

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Positive test.

Event B: Having breast cancer.

3.65% of women in their 60s get breast cancer

This means that P(B) = 0.0365

A mammogram can typically identify correctly 85% of cancer cases

This means that P(A|B) = 0.85

Probability of a positive test.

85% of 3.65% and 100-95 = 5% of 100-3.65 = 96.35%. So

P(A) = 0.85*0.0365 + 0.05*0.9635 = 0.0792

What is the probability that a woman in her 60s who has a positive test actually has breast cancer?

P(B|A) = \frac{0.0365*0.85}{0.0792} = 0.3917

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer

7 0
3 years ago
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