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Assoli18 [71]
2 years ago
15

Are the ratios 7:11 and 9:13 equal?

Mathematics
2 answers:
Gemiola [76]2 years ago
7 0
No, because 7/11 = 0.63 repeating and 9/13 = 0.69
Shtirlitz [24]2 years ago
6 0
No because 7/11 is 0.(63) and 9/13 is 0.692
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Write a quadratic equation in the form x² + bx+c=0 that has the following
vfiekz [6]

Answer:

x^2-6x+5

Step-by-step explanation:

To have roots at x=5 and x=1 you need to write is as follows

(x-5)(x-1)

you then need to multiply these two and get

x^2-6x+5

7 0
3 years ago
A furniture store owner buys a sofa for $400 and marks it up 90% to sell it. During the store's anniversary sale, she sells the
nydimaria [60]

Answer:

$570

Step-by-step explanation:

If she marks up the sofa for 90%, she will change the price to 760$

Now, 25% of 760$ is 190$. So, we subtract 190 from 760 and get 570$

Hope this helped, and have a good one!

7 0
2 years ago
What would be 80.9 km to cm
tatyana61 [14]

Answer:

80.9 kilometres =

8090000 centimetres

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8090000

Centimeter

3 0
3 years ago
A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.
yKpoI14uk [10]

The correct statement is:

  • There are four ways to choose the committee.
  • There are three ways to form the committee if person D must be on it.
  • If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

#SPJ4

<em>Your question is incomplete. Please read below to find the missing content.</em>

<em />

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

8 0
2 years ago
Replace with &lt;,&gt;, or = to make a true statement: 2^5 4^2
Crank

Answer:

2^5>4^2

Step-by-step explanation:

{2}^{5}  >  {4}^{2}  \\ 32 > 16

hopefully this makes sense

:)

3 0
2 years ago
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