Answer:
1 / 4c+5
Step-by-step explanation:
Given :
4c + 5 ≠ 0
c is a real number.
Find the multiplicative inverse of equation ?
The multiplicative inverse of a number is reciprocal of number
Let
x = a number
The multiplicative inverse = 1/x
Let 4c + 5 ≠ 0 be a number x
Then, the multiplicative inverse of x = 1/x
x = 4c + 5
1/x = 1 / 4c+5
Therefore, the multiplicative inverse of 4c + 5 = 1 / 4c+5
Subtracting a number from x shifts the graph that may places tot he right
Subtracting a number at the end of the equation, shifts the graph that many units down.
The answer would be: Shift the graph of y = x^2 right 2 units and then down 10 units.
The new size of cube's side is 6. V new cube = 6*6*6 = 216
3.5, y2-y1 / x2-x1 or rise/run
Pattern A starts with 20 and substracts 3
First number = 20
Second number = 20 - 3 = 17
Third number = 17 - 3 = 14
Fourth number = 14 - 3 = 11
Pattern B starts with 10 and adds 2
First number = 10
Second number = 10 + 2 = 12
Third number = 12 + 2 = 14
Fourth number = 14 + 2 = 16
Now join pattern A and B
First combination = (20,10)
Second combination = (17,12)
Third combination = (14, 14)
Fourth combination = (11, 16)
The answer is d. (20,10), (17,12), (14,14), (11,16)
