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3 years ago

What is the simplified form of x plus 5, all over 9 minus x plus 4, all over x plus 6 ?

Mathematics

1 answer:

Fudgin [204]3 years ago

5 0

Find the common denominator:

(x+6)(x+5) - 9(x+4)
_______________
9(x+6)

x^2 + 2x - 6
__________
9(x+6)

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a storage jug was 4/5 full of water when did get indicated 72 what was the full capacity of the storage jug

IRISSAK [1]

Answer:

90. ( was the full capacity of jug)

to solve this 

firstly let the full capacity of jug 

 

be. x

so, 

4/5*x = 72

x = 72*5/4

x = 90

hope it helps

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3 years ago

Find the area of the parallelogram shown below. 14 square units

kicyunya [14]

Answer would be 140 why does my answer need to be 20 words long ugh

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3 years ago

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The number of students in a chess club decreased from 28 to 11. What is the percent decrease? Round your answer to the nearest p

atroni [7]

Answer:

28-11=17

28=100%

17=x

17×100/28=60,71

rounded 61%

60,71%

11/28*100=a

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to nearest percent 61 i think

8 0

2 years ago

Simplify: 6y + 5z + 8y – 3z

mezya [45]

Combine like terms. 6y + 8y is 14y. 5z - 3z is 2z. so the answer is 14y + 2z.

4 0

3 years ago

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The board of a large company is made up of 7 women and 9 men. 6 of them will go as a delegation to a national conference.

Burka [1]

Answer:

a) 5765760

b) 60480

c) 5705280

Step-by-step explanation:

Assuming that order is not important:

Number of women = 7

Number of men = 9

Members of the delegation = 6

a) How many delegations are possible?

$n=\frac{16!}{(16-6)!}=16*15*14*13*12*11\\ n= 5765760$

b) How many of these delegations have all men?

$n_{men} = \frac{9!}{(9-6)!}=9*8*7*6*5*4 \\n_{men} = 60480$

c) How many of these delegations have at least one woman?

$n_{women >0}=n-n_{men}\\n_{women >0} =5765760-60480\\n_{women >0} =5705280$

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3 years ago