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3 years ago

Find the intercepts of -5x+4y =20 when x=0 and y=0

Mathematics

1 answer:

marishachu [46]3 years ago

5 0

-5 x 0 = 0
4 x y = 0
Therefore,
0 = 20.
Hope this helps?

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Help please, id really appreciate it

Angelina_Jolie [31]

Answer:

Domain: [-2, 2]

Range: [-3, 3]

Step-by-step explanation:

Domain (x) is the left and right. Range (y) is the up and down.

It's a bracket if it is included, meaning, there is no gap or hole.

If it weren't included, it'd be a parentheses instead "( )". For example, if there was an open circle.

It would go to -infinty or +infinity if it were to go on forever, and that would be in parentheses.

EX: (-∞,∞) or (-∞, 8]

You can mix and match the brackets and parentheses depending on whether or not it touches/includes the number, like I've mentioned.

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3 years ago

What's the distance between 178 and -395

Svet_ta [14]

178 - (-395)

178 + 395 = 573

the distance between -395 and 178 is 573

hope this helps

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3 years ago

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nikklg [1K]

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3 years ago

How many times will 2.09 go into 22.5

DENIUS [597]

all you have to do is add 2.09 to itself until it gets to 22.5

2.09 x 10 = 20.9

2.09 x 11 = 22.99

so, 2.09 goes into 22.5 ten times

3 0

3 years ago

Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ

mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...

Anyways, the half angle identity for tangent is

$tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}$

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }$ which simplifies a bit to

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{5}{5} -\frac{4}{5} }$ and a bit more to

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{1}{5} }$

Bring up the lower fraction and flip it to divide to get

$tan(\frac{\theta}{2})=-\frac{3}{5}*\frac{5}{1}$ which of course simplifies to

-3. Choice A.

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3 years ago