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Olenka [21]
3 years ago
8

Help AS SOON AS POSSIBLE PLEASE HELP

Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

Answer:

R.I.P Gl man im lost...

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Use the discriminant to determine how many real number solutions exist for the quadratic equation –4j2 + 3j – 28 = 0. A. 3 B. 2
Zepler [3.9K]

Answer:

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Step-by-step explanation:

–4j^2 + 3j – 28 = 0

The discriminant is b^2-4ac  if >0 we have 2 real solutions

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9 -448

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4 years ago
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the answer would be.......

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