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uysha [10]
3 years ago
14

Evaluate the expression for the value given. 8(7 - x) ; f or x = 2

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0
Plug 2 in for x then 7-2 equals 5 then multiply that by 8 which gives you 40
ivann1987 [24]3 years ago
6 0

Answer:

40

Step-by-step explanation:

Substitute x for 2.

8(7-2)

8(5)

x=40

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I need help on this how do you find the third measure
Goryan [66]
The sum of the three angles of a triangle is always 180°. Tha is
  (first measure) + (second measure) + (third measure) = 180°

Subtract the first two terms of this equation and you have
  (third measure) = 180° - (first measure) - (second measure)

a. third measure = 180° - 45° - 55° = 80°

b. third measure = 180° - 50° - 40° = 90°

c. third measure = 180° - 110° - 35° = 35°

4 0
3 years ago
If M (6,8) is the midpoint of line segment AB, and if A has coordinates (2,3) , find the coordinates of B.
sveticcg [70]
Graphing is one way to do the problem.But sometimes, graphing it is hard to do.So here’s an algebraic method.
If M(m1, m2) is the midpoint of two points A(x1, y1) and B(x2, y2),then m1 = (x1 + x2)/2 and m2 = (y1 + y2)/2.In other words, the x-coordinate of the midpointis the average of the x-coordinates of the two points,and the y-coordinate of the midpointis the average of the y-coordinates of the two points.
Let B have coordinates (x2, y2) in our problem.Then we have that 6 = (2 + x2)/2 and 8 = (3 + y2)/2.
Solving for the coordinates gives x2 = 10, y2 = 13
8 0
3 years ago
1. y = x2 + 8x + 15<br> Find the zeros of the function by rewriting the function in intercept form
lubasha [3.4K]

The zeros of given function y=x^{2}+8 x+15 is – 5 and – 3

<u>Solution:</u>

\text { Given, equation is } y=x^{2}+8 x+15

We have to find the zeros of the function by rewriting the function in intercept form.

By using intercept form, we can put value of y as  to obtain zeros of function

We know that, intercept form of above equation is x^{2}+8 x+15=0

\text { Splitting } 8 x \text { as }(5+3) x \text { and } 15 \text { as } 5 \times 3

\begin{array}{l}{\rightarrow x^{2}+(5+3) x+5 \times 3=0} \\\\ {\rightarrow x^{2}+5 x+3 x+5 \times 3=0}\end{array}

Taking “x” as common from first two terms and “3” as common from last two terms

x (x + 5) + 3(x + 5) = 0

(x + 5)(x + 3) = 0

Equating to 0 we get,

x + 5 = 0 or x + 3 = 0

x = - 5 or – 3

Hence, the zeroes of the given function are – 5 and – 3

5 0
3 years ago
HELP ME PLEASE.......
lesantik [10]
First and the fourth
8 0
3 years ago
The annual interest rate on a $10,000 loan is 18%. The exponential function that represents this is y = 10000(1.18t). Write the
Yuki888 [10]

Answer:

y=10000(1.015)^{12t}

option-B......Answer

Step-by-step explanation:

We are given

amount taken for loan =$10000

so, P=10000

annual interest rate =18%

r=0.18

now, we can use formula

y=P(1+\frac{r}{n} )^{nt}

Since, it is compounded monthly

so, n=12

we can plug values

y=10000(1+\frac{0.18}{12} )^{12t}

y=10000(1.015)^{12t}

6 0
3 years ago
Read 2 more answers
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