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2 years ago

Determine the sum of the first 1000 Natural numbers

Mathematics

1 answer:

levacccp [35]2 years ago

8 0

Answer:

Numbers Sum

1-10 55

1-100 5050

1-1000 500500

Step-by-step explanation:

55+ 5050=

500500

500500 is a sum of number series from 1 to 1000 by applying the values of input parameters in the formula. Natural numbers or positive integers from 1 to 1000 by applying arithmetic progression. (to find it)

mark me brainiest

pls and ty

hope this helps!!

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Anyone, please help I really need to know ?

wel

I don’t know how to explain but I can work out the correct ans
To find how much is needed for one person
280/4=70
For 10 person:70*10=700

6 0

3 years ago

The circumference of Tyler's bike tire is 72 inches. What is the diameter of the tire?

pantera1 [17]

Answer:

The diameter is 22.92 inches

Step-by-step explanation:

Hello, I can help you with this question

in this case we know the circumference of a circle, and we need to find out the diameter.

let's remember

the radius of a circle can be defined as

$radius=\frac{diameter}{2}\\ or\\diameter=2* radius( equation\ 1)\\$

also

$circumference=2*\pi *radius(equation2)\\$

Step1

replace the value of the circumference of tyler's bike in equation 2 and isolate radius to find radius

$72 inches=2*\pi *radius\\\\radius=\frac{72}{2*\pi } \radius =11.46\ inches$

Step 2

now, replace the value of radius into equation 1 to find diameter

radius=11.46 in

$diameter=2* radius( equation\ 1)\\\\diameter=2*11.46\\diameter=22.92$

so, the diameter is 22.92 inches

I really hope it helps, have a great day.

5 0

2 years ago

Read 2 more answers

This math my graduation depends on it

In-s [12.5K]

In an arithmetic sequence, consecutive terms have a fixed distance d between them. If a₁ is the first term, then

2nd term = a₂ = a₁ + d

3rd term = a₃ = a₂ + d = a₁ + 2d

4th term = a₄ = a₃ + d = a₁ + 3d

and so on, up to

nth term = $a_n = a_{n-1} + d = a_{n-2} + 2d = a_{n-3} + 3d = \cdots = a_1 + (n-1)d$

so that every term in the sequence can be expressed in terms of a₁ and d.

6. It's kind of hard to tell, but it looks like you're given a₁₃ = -53 and a₃₅ = -163.

We have

a₁₃ = a₁ + 12d = -53

a₃₅ = a₁ + 34d = -163

Solve for a₁ and d. Eliminating a₁ and solving for d gives

(a₁ + 12d) - (a₁ + 34d) = -53 - (-163)

-22d = 110

d = -5

and solving for a₁, we get

a₁ + 12•(-5) = -53

a₁ - 60 = -53

a₁ = 7

Then the nth term is recursively given by

$a_n = a_{n-1}-5$

and explicitly by

$a_n = 7 + (n-1)(-5) = 12 - 5n$

7. We do the same thing here. Use the known terms to find a₁ and d :

a₁₉ = a₁ + 18d = 15

a₃₈ = a₁ + 37d = 72

⇒ (a₁ + 18d) - (a₁ + 37d) = 15 - 72

⇒ -19d = -57

⇒ d = 3

⇒ a₁ + 18•3 = 15

⇒ a₁ = -39

Then the nth term is recursively obtained by

$a_n = a_{n-1}+3$

and explicitly by

$a_n = -39 + (n-1)\cdot3 = 3n-42$

8. I won't both reproducing the info I included in my answer to your other question about geometric sequences.

We're given that the 1st term is 3 and the 2nd term is 12, so the ratio is r = 12/3 = 4.

Then the next three terms in the sequence are

192 • 4 = 768

768 • 4 = 3072

3072 • 4 = 12,288

The recursive rule with a₁ = 3 and r = 4 is

$a_n = 4a_{n-1}$

and the explicit rule would be

$a_n = 3\cdot4^{n-1}$

7 0

2 years ago

Does anyone have the answers for all?

Shkiper50 [21]

Answer and Step-by-step explanation:

1-6

What you can do is plug in 6 and start by doing the first machine first, then the second. If this doesn't work, do the second machine, then the first machine.

The order that works is second machine, then first machine.

Second Machine:

y = $(6)^{2} -6$ = 36 - 6 = 30

Plug into first machine now.

First Machine:

y = $\sqrt{(30) - 5} = \sqrt{25} = 5$

We see that the result is 5.

b. If we were to do the order of second machine, then first machine, we will never get a negative result (or -5 for that matter), due to the fact that you can't algebraically square root a negative number.

However, if we were to do the order of first machine, second machine, we can get a negative number. To get -5, we plug in 6 for x in the first machine, getting an answer of 1. We plug this into the second machine, getting 1^2 - 6, which results in -5.

1-7. The absolute value of a value is the positive version of that value.

a. |54| = 54

b. $-|-7\frac{3}{5}|$ = $-7\frac{3}{5}$

c. |3| - |-1| = 3 - 1 = 2

d. |2.2 - 5.13| = |-2.93| = 2.93

1-8.

| |

| |

| || || || || |

(5 boxes on each side)

| |

| |

| || || || || || |

(6 boxes on each side)

b. The amount of squares on each side of the figure increases by 1.

c. There would be 1 square, because we know that the pattern is there is 2 squares added to the next figure, 1 at each end. If we go back a figure, we take away 2 squares.

1-9.

a. -42 - 17 = -59

b. 8 - (-9) = 8 + 9 = 17

c. 8(-9) = -72

d. -42 ÷ (-7) = 6

e. -2(-3)(-4) = 6(-4) = 24

f. -18 - 7 = -25

g. $(-5)^{2}$ = 25