Question

Help me out please ty!

Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's solve ~

$\qquad \tt \dashrightarrow \:a1 = 4$

Now, let's proceed next till we get$\tt a_5$

$\qquad \tt \dashrightarrow \: a_2 = - 4a_{(2 - 1)}+ 5$

$\qquad \tt \dashrightarrow \: a_2 = - 4a_{1}+ 5$

$\qquad \tt \dashrightarrow \: a_2 = (- 4 \times 4)_{}+ 5$

$\qquad \tt \dashrightarrow \: a_2 = - 16_{}+ 5$

$\qquad \tt \dashrightarrow \: a_2 = - 11$

Similarly,

$\qquad \tt \dashrightarrow \: a_3 = 49$

$\qquad \tt \dashrightarrow \: a_4= - 191$

Now, let's solve for $\tt a_5$

$\qquad \tt \dashrightarrow \: a_5= - 4( - 191) + 5$

$\qquad \tt \dashrightarrow \: a_5= 764 + 5$

$\qquad \tt \dashrightarrow \: a_5= 769$

Answer 2

Answer:

a5 = 2604

Step-by-step explanation:

a1 = 4

a2 = -5(4)-1 = -21

a3 =-5(-21)-1 = 104

a4 = -5(104)-1 =-521

a5 =-5(-521)-1 = 2604