Answer:
- f(t) = 6000*1.03^t
- k = 0.0295588
Step-by-step explanation:
The formula for exponential growth can be written a couple of different ways. One I prefer uses the problem numbers directly:
population = (initial population) × (growth factor)^t
Here, the initial population is 6000, and the growth factor is 1+3% = 1.03. Then the function can be written as ...
f(t) = 6000·1.03^t
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Another way to write the function is using the form ...
f(t) = (initial population) × e^(kt)
where k is the natural logarithm of the growth factor. In this form, we have ...
k = ln(1.03)
k ≈ 0.0295588
so the function would be written ...
f(t) = 6000·e^(0.0295588t)
I belive the answer should be similar
Y2-y1/x2-x1 = 7-8/-3-4=-1/-7 =1/7
It’s showing you that’s it’s a squared number
for example, 5^2 = 5 squared = 25
At the end of the third year the population of beetles will be 11,576beetles
<h3>Exponential equations</h3>
The standard form of an exponential function is given as:
y = ab^t
Given the following parameters
initial population 'a" = 10,000 beetles
Time = 3 years
rate b = 1.05
Substitute into the formula
y = 10,000(1.05)^3
y = 10,000(1.1576)
y = 11,576 beetles
Hence at the end of the third year the population of beetles will be 11,576beetles
Learn more on exponential function here: brainly.com/question/12940982
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