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2 years ago

Does the system of equations have no solution, one solution, or an infinite number of solutions? −5x+y=−1−5x+y=10

Mathematics

2 answers:

kherson [118]2 years ago

5 0

Answer:

5x-y=9, y=5x+19 write both equations in same formy=5x-9 for the first and havey=5x+19 for the second. These are two parallel lines with different intercepts. They do not intersect or coincide. No solutions

and y=6x+14, 12x-2y=-28 write both equations in same formy=6x+142y=12x+28 or y=6x+14. They are the same line. The solution is all of the points on the line.

Step-by-step explanation:

I hope it will help you have a great day bye and Mark brainlist if the answer is correct I am sorry if the answer is worng 

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#carry on learning

harina [27]2 years ago

5 0

Answer:

Step-by-step explanation:

Are these the two equations?

−5x+y=−1

−5x+y=10

=====

Put them into slope-intercept form of y = mx + b

−5x+y=−1

y = 5x - 1

−5x+y=10

y = 5x + 10

Both have a slope of 5, so they will not intersect. This means there are no solutions.

See attached graph.

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Tan(x-y) if cscx=13/5 and coty=4/3

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Answer:

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Step-by-step explanation

Tan(x-y) if cscx=13/5 and coty=4/3

Given

coty = 4

1/tany = 4/3

Cross multiply

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Also since cscx = 13/5

1/sinx = 13/5

sinx = 5/13

Since sinx = opp/hyp

opp = 5

hyp = 13

Get the adjacent

hyp² = opp²+adj²

13² = 5²+adj²

adj² = 13² - 5²

adj² = 169 - 25

adj² = 144

adj = 12

cosx = adj/hyp

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tanx = sinx/cosx

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tanx = 5/13 * 13/12

tan x = 5/12

tan(x-y) = tanx - tany/1+tanxtany

tan(x-y) = (5/12 - 3/4)/1+(5/12)(3/4)

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