Answer:
(A)
Step-by-step explanation:
Using the formula :
Area = 1/2 [-1(1 - 6) -7(6 - 1) -3(1 - 1)]
Area = 1/2 [5 - 35]
Area = 1/2 × -30 = |-15| = 15 units²
Answer:
<h2>x=2</h2><h2>y=4</h2>
Step-by-step explanation:
5x-y=6
2x+y=8
add them up
7x=14
divide by 7 to get x
x=2
fit it into both equation
y=4
Answer: The answer is the first explanation.
Step-by-step explanation: We are given five different options and we are to select which explanation is correct to derive the formula for a circumference of a circle.
Let 'C' be the circumference and 'd' be the diameter of a circle. Now, we will write the ratio of the circumference to the diameter as

Also, we know that

And diameter of a circle is twice the radius, so

Therefore,

This is the formula for the circumference of a circle. Since this explanation matches exactly with the first option, so the correct option is
(a). Find the relationship between the circumference and the diameter by dividing the length of the circumference and length of the diameter. Use this quotient to set up an equation to showing the ratio of the circumference over the diameter equals to π . Then rearrange the equation to solve for the circumference. Substitute 2 times the radius for the diameter.
[ Answer ]

[ Explanation ]
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LCM - The smallest number that two or more numbers can evenly fit into
- LCM - What We Know
- 2 & 13 Must Evenly Fit
- Must Be Smallest Number They Both Fit Into
- Multiple Of Two Or More Numbers
The Smallest Number That Both 2 & 13 Evenly Fit Into Is 26
26 ÷ 2 = 13
26 ÷ 13 = 2
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Answer:
Function 2 has a greater initial valueStep-by-step explanation:An initial value of a function, aka y-intercept, is obtained by using x=0 and evaluating the function at that point. Evaluating the two functions given:Function1: Function2 has value 3 for x=0So, Function 2 has a greater initial valueFunction 2 has a greater initial valueStep-by-step explanation:An initial value of a function, aka y-intercept, is obtained by using x=0 and evaluating the function at that point. Evaluating the two functions given:Function1: Function2 has value 3 for x=0So, Function 2 has a greater initial value
Step-by-step explanation: