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2 years ago

Solve for p: p/10 = 7.2/36

Mathematics

1 answer:

vovikov84 [41]2 years ago

3 0

P=20 this is because you have to get 2 on each side 7.2/3.6 =2 so 20/10=2 2=2

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PLZ HELP NEED ASAP, much appreciated

Margaret [11]

Answer:

Ok that's not it

x=-1 then y=4

x=0 then y= 6

x=1 then y = 8

x=2 then y= 10

x=3 then y= 12

Step-by-step explanation:

when y=2x+6

you have to plug what it says x is in each of the equations.

For the first one it says x=-1

you then plug that in and you get y=2(-1)+6

then you go through PEMDAS and first you get y=-2+6

-2+6 = 4

therefore y=4

and you just go through the rest wiht that

Step-by-step explanation:

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1 year ago

The zeros of a function are the values of x for which the function is equal to zero. Enter a number in each blank to make trued

scoray [572]

Answer:

zeros are 4 and 3

Step-by-step explanation:

2x - 6 =0

x -4 = 0

solve both of these for x

these are your zeros

7 0

2 years ago

In a pair of triangles, if two pairs of corresponding sides are proportional, and the angles in between the two pairs of corresp

Anna007 [38]

Answer: B, x = 2.25 cm

8 0

3 years ago

Read 2 more answers

Juanita says that 3.5[4d - (2) (1.5)] and 2[7d - (5)(1.05)] are equivalent. Is Juanita correct? Explain your reasoning.

valkas [14]

Answer:

Yes

Step-by-step explanation:

3.5 [4d - 2*1.5] = 3.5*4d - 3.5*2*1.5

= 14d - 10.5

2*[7d - 5*1.05] = 2*7d - 2*5*1.05

= 14d - 10.5

When we are simplifying both the expression using distributive property, we get the same expression at the end.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%

Llana [10]

a) The given function is

$f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}$

The domain refers to all values of x for which the function is defined.

The function is defined for

$x^4+x^3-4x^2-4\ne0$

This implies that;

$x\ne -2.69,x\ne 1.83$

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

$x^4+x^3-4x^2-4=0$

This implies that;

$x= -2.69,x=1.83$

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

$\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

$\Rightarrow x^2-4=0$

$x^2=4$

$x=\pm \sqrt{4}$

$x=\pm2$

The roots are $x=-2,x=2$

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

$x=0$ into the function

$f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}$

$f(0)=\frac{-4}{-4}=1$

e) to find the horizontal asypmtote, we take limit to infinity

$lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

The horizontal asymtote is $y=0$

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

6 0

2 years ago