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2 years ago

Determine the relationship between the two triangles and whether or not they can be proven to be congruent

Mathematics

1 answer:

pishuonlain [190]2 years ago

6 0

Answer:

SAS congruence postulate

Step-by-step explanation:

It is given that two sides are congruent and one included angle is also congruent, this is enough to use the SAS congruence postulate and prove the triangles congruent.

Hope this helps

Please mark brainliest ;)

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Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?

alexgriva [62]

Answer:

x Superscript 9 Baseline (RootIndex 3 StartRoot y EndRoot)

OR x^9/(∛y)

Step-by-step explanation:

Given the indicinal equation

(x^27/y)^1/3

To find the corresponding expression, we will simplify the equation as shown:

(x^27/y)^⅓

= (x^27)^⅓/y⅓

= {x^(3×9)}^⅓/y⅓

= x^9/y⅓

= x^9/(∛y)

The right answer is x Superscript 9 Baseline (RootIndex 3 StartRoot y EndRoot)

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The opposite of negitive thirty-six

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The opposite of -36 is equal to 36

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3 years ago

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Could someone help me rnnn?

GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola: $y=3x^2-4$

Step-by-step explanation:

Given:

y-intercept of parabola: -4
parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola: $y=a(x-h)^2+k$

(where (h, k) is the vertex and $a$ is some constant)

Substitute point (0, -4) into the equation:

$\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}$

Substitute point (-2, 8) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}$

Substitute point (1, -1) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}$

Equate to find h:

$\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}$

Substitute found value of h into one of the equations to find a:

$\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}$

Substitute found values of h and a to find k:

$\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}$

Therefore, the equation of the parabola in vertex form is:

$\implies y=3(x-0)^2-4=3x^2-4$

So the vertex of the parabola is (0, -4)

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3 years ago

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PLEASE HELP ME!!!!!!

Sonja [21]

Answer:

$\huge \red{ c_3 = - 1}$

Step-by-step explanation:

$c_1 = 1 \\ \\ c_n= - 2c_{n-1}+5 \\ \\ c_2 = - 2c_{2-1}+5 \\ \\ c_2 = - 2c_{1}+5 \\ \\ c_2 = - 2(1)+5 \\ \\ c_2 = - 2+5 \\ \\ \huge \purple{c_2 =3} \\ \\ c_3 = - 2c_{3-1}+5 \\ \\ c_3 = - 2c_{2}+5 \\ \\ c_3 = - 2(3)+5 \\ \\ c_3= - 6+5 \\ \\ \huge \red{ c_3 = - 1}$

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3 years ago