Answer:
D) 100 ≤ y ≤ 400
Explanation:
When we are talking about range, we are talking about y values, so B is disqualified.
When determining range you want the lowest & highest y values.
On this graph the lowest value of y is 100 (seen between 5 and 6 seconds).
The highest value of y is 400 (seen at 8 seconds).
Therefore, 100 ≤ y ≤ 400.
M=14.6 (is rounded to the nearest tenth.)
2-4=2
(-2)+4=2
2+4=6
Why is this a question
I'm assuming the two cars start from the same point!
<span>Let's measure time t from the time when Car 2 starts. </span>
<span>Then the distances travelled by the cars up to the time of overtaking, t, must be the same. </span>
<span>And we need to measure all time in hours, so 18 mins. is 0.3 hours. </span>
<span>So, 45 x (0.3 + t) = 65 x t, so 20t = 13.5, so t = 13.5/20 = 27/40 = 40.5/60, i.e. 40 min 30 sec</span>