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2 years ago

Identify an equation in point-slope form for the line parallel to y = 3x-7 that

2 answers:

8 0

Answer:The equation of the line parallel to (3x - y = 7) passes through the point (-5, -3) is y = 3x + 2 and this can be determined by using the one-point slope form.

Bess [88]2 years ago

7 0

Answer:

B. y + 2 = 3(x + 3)

Step-by-step explanation:

Given line:

y = 3x - 7

Its slope is 3.

The parallel line has same slope and passes through ( - 3, - 2).

Its equation is:

y - (- 2) = 3(x - (-3))
y + 2 = 3(x + 3)

Correct choice is B

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Which graph is defined by the function given below? y= (x + 2)(x+7)

Lady bird [3.3K]

Answer:

A parabola

Step-by-step explanation:

It's a quadratic equation so the graph will be a parabola.

The solutions are -2 and -7

8 0

3 years ago

A piece of wood weighing 10 ounces is found to have of 8 ounces after drying . The moisture content was

ollegr [7]

20%, I believe. The piece of wood lost 2 ounces of moisture after drying, and 2/10 = 20/100

8 0

3 years ago

Patty wants a triangle garden in her backyard for all of her vegetables. She

otez555 [7]

Answer:

Step-by-step explanation:

the hypothenuse is the largest side in the right triangle

we have 2 side, 7,8

in a right triangle, c^2= a^2+b^2

where c is the hypothenuse

c^2=49+64=113

c=sqrt113=aprox 10.6

so, the answer is no if it has to be exactly 10 ft the hypotenuse

5 0

3 years ago

Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ

mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...

Anyways, the half angle identity for tangent is

$tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}$

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }$ which simplifies a bit to