All categories

4 years ago

I need help with 2-5 please

Mathematics

1 answer:

babymother [125]4 years ago

6 0

Answer:

plppppppppp

Step-by-step explanation:

You might be interested in

Mary and Frank combine the marbles into one bag to do an experiment where they pick a marble from a bag and toss a coin. In the

Strike441 [17]

Answer:if We should put it in a decimal it’s 0.1 as a fraction it’s 11/110

Step-by-step explanation: You have to add all the numbers from the table and then add 11 wich makes it 11/110 you also add 11 beacahss it’s how many times yellow has landed on tails hope I am right

3 0

3 years ago

This is worth 25(50)points please answer this is asap! there are three questions!

Alenkinab [10]

Answer:number 1 is x<6750number 2 is $22.05 number 3 is $105

Step-by-step explanation:

4 0

3 years ago

(Find the Probability Question)<br><br> Choose 2 girls from a class of 12 boys and 8 girls.

Ulleksa [173]

Step-by-step explanation:

what should be the question ?

how many different pairs of 2 girls can you pick out of 8 ?

what is the probability that a specific girl is in the picked pair ?

or is it : if you pick randomly 2 students from the class, what is the probability to have picked 2 girls ?

and there are more options.

but I assume the problem is the picking randomly 2 students.

so, it is 20 students (12 + 8). if we pick 1 student, we have a chance of 12/20 = 3/5 to pick a boy, and a chance of 8/20 = 2/5 to pick a girl.

in our experiment we pick 2 students in a row without returning the first pick into the main pool.

the probabilty for the first pick to be a girl is, as mentioned, 2/5 or 0.4.

for the second pick we have only 7 out of 19 choices to pick a girl. so, the probability to pick a girl now is 7/19.

the combination of both (non-overlapping) probabilities is done via multiplication, and the probabilty to pick 2 girls is :

2/5 × 7/19 = 2×7 / 5×19 = 14/95 = 0.147368421...

7 0

2 years ago

| x-3 | < x-3<br><br> can someone give a step by step process on how to do this?

statuscvo [17]

Answer:

There are no solutions to the inequality.

Step-by-step explanation:

|x - 3| < x – 3

1. Separate the inequality into two separate ones.

(1) x – 3 < x – 3

(2) x – 3 < -(x – 3)

2. Solve each equation separately

(a) Equation (1)

$\begin{array}{rcl}x - 3 & < & x - 3\\x & < & x\\\end{array}\\\text{This is impossible. No solutions exist.}$

(b) Equation (2)

$\begin{array}{rcl}x - 3 & < & -(x - 3)\\x - 3 & < & -x + 3\\x &$

For example, if x = 0, we get

|0 - 3| < 0 - 3 or

3 < -3

4 0

4 years ago

(WILL GIVE BRAINLIEST)Find the polynomial function with real coefficients that has zeros 1, 1 , 2+ i sqrt 3

neonofarm [45]

Answer:

$x^3-x^2(4+i\sqrt{3} )+x(5+i2\sqrt{3} )-(2+i\sqrt{3} )=0$

Step-by-step explanation:

We have given that this polynomial has the given zeroes of 1, 1, and $2+i\sqrt{3}$ , we can express the polynomial in a factored form where each zero has the form x-a (where a is our zero):

polynomial= $(x-1) (x-1) (2+i\sqrt{3})$

= $(x^2+1-2x) (2+i\sqrt{3})$

= $x^3-x^2(4+i\sqrt{3} )+x(5+i2\sqrt{3} )-(2+i\sqrt{3} )=0$

8 0

4 years ago