Write the equation in standard form. Identity the center and radius. x² + y2 + 8x-4y-7=0

Mathematics

1 answer:

Masteriza [31]2 years ago

3 0

Answer:

See below

Step-by-step explanation:

Given equation:

x² + y² + 8x - 4y - 7 = 0

Convert this to standard form by completing the square:

(x - h)² + (y - k)² = r², where (h, k) - center, r - radius
x² + 2*4x + 4² + y² - 2*2y + 2² - 16 - 4 - 7 = 0
(x + 4)² + (y - 2)² - 27 = 0
(x + 4)² + (y - 2)² = 27
(x + 4)² + (y - 2)² = (√27)²

The center is (- 4, 2) and the radius is √27

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