First thing to know so that we can determine the amount you will pay is to understand the other cost made on the jeans. It is said that it is on sale for 25% this means that this certain amount should be subtracted. Another cost is the tax wherein you have to add this amount. We calculate as follows:
Cost = 26.49 - 26.49x.25 + 26.49x.0475 = 21.13
9 c 10 b 11 b 12a 13 c 14 d 15 d 16c 17 a or c
18 b 19 d 20 is b
Answer:
31 pencils
Step-by-step explanation:
What we must do is reduce the range of responses, the first thing is to limit the numbers to the interval between 30 and 40.
If it is two by two and there is one left, it means that all the pairs are eliminated.
If it is five in five and there is one left over, the ones ending in 5 are also eliminated.
If it is three by three and there is one left over, the 33 and 39 are eliminated.
Taking this into account, the possibilities are reduced to two numbers only, 31 and 37.
37 is discarded because when it is grouped from five to five, there are 2 left over.
So the answer is 31, you have 31 pencils.
Answer: The answer would be B
<u>Write out the equation in slope-intercept form: </u>
y=-5/3x+6 (Once we know that, it'll be easier to convert it into standard form.)
<u>Subtract -5/3 from both sides of the equation:</u>
y+5/3x=6
<u>Subtract 6 from both sides:</u>
y+5/3x-6=0
<u>Multiply both sides by 3 to get rid of the fraction:</u>
3y+5x-18=0
<u>Then arrange the numbers to x and y are on one side by itself:</u>
3y+5x=18
<em>And that's your answer!</em>
<em />
Hope this helped you!
Answer:
D
Step-by-step explanation:
<em>for </em><em>you </em><em>to </em><em>find </em><em>x </em><em>you </em><em>first </em><em>have </em><em>to </em><em>find </em><em>the </em><em>adjacent</em><em> </em><em>of </em><em>the </em><em>4</em><em>5</em><em>°</em><em> </em><em>angle </em><em>you </em><em>can </em><em>do </em><em>that </em><em>by </em><em>using</em><em> </em><em>the </em><em>other </em><em>triangle.</em><em>u</em><em>s</em><em>i</em><em>n</em><em>g</em><em> </em><em>the </em><em>sin </em><em>ratio</em>
<em>sin60=</em><em>opposite</em><em>/</em><em>hypotenuse</em>
<em>sin60=</em><em>a/</em><em>7</em><em>√</em><em>3</em>
<em>a</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>
<em>then </em><em>after </em><em>you </em><em>have </em><em>found</em><em> </em><em>the </em><em>adjacent</em><em> </em><em>you </em><em>can </em><em>use </em><em>the </em><em>cos </em><em>ratio</em>
<em>cos45=</em><em>adjacent/</em><em>hypotenuse</em>
<em>cos45=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>/</em><em>x</em>
<em>cos45x/</em><em>cos45=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>/</em><em>cos45</em>
<em>x=</em><em>1</em><em>4</em><em>.</em><em>8</em><em>4</em><em>9</em>
<em>which </em><em>is </em><em>the </em><em>same </em><em>as </em><em>2</em><em>1</em><em>√</em><em>2</em><em> </em><em>over </em><em>2</em>
<em>I </em><em>hope</em><em> this</em><em> helps</em>
