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Mama L [17]
3 years ago
14

What is the value of the digits 1.05

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
5 0

Answer:

1 : ones

0 : tenths

5 : hundredths

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\bf f(x)=\sqrt{cos(6x)}\implies f(x)=[cos(6x)]^{\frac{1}{2}}
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f'(x)=\stackrel{\textit{using the chain-rule}}{\cfrac{1}{2}[cos(6x)]^{-\frac{1}{2}}~\cdot ~-sin(6x)~\cdot ~6}\implies f'(x)=\cfrac{-6sin(6x)}{2[cos(6x)]^{\frac{1}{2}}}
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f'(x)=\cfrac{-3sin(6x)}{\sqrt{cos(6x)}}
\\\\[-0.35em]
\rule{34em}{0.25pt}


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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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