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2 years ago

Solve the literal equation for the indicated variable. Show your work. P=2(l+w) for l.

Mathematics

1 answer:

Norma-Jean [14]2 years ago

3 0

Answer:

l = P/2 -w

Step-by-step explanation:

P=2(l+w)

Divide each side by 2

P/2 = 2(l+w)/2

P/2 = l+w

Subtract w from each side

P/2 -w = l+w-w

P/2 -w =l

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If f(x) =1/9 x-2, what is f-1(x)?

Sav [38]

Answer:

f^-1(x) = 9(x+2)

Step-by-step explanation:

To find the inverse function, exchange x and y and then solve for y

y = 1/9 x -2

Exchange x and y

x = 1/9 y-2

Solve for y

Add 2 to each side

x+2 = 1/9 y-2+2

x+2 = 1/9y

Multiply each side by 9

9(x+2) = 9*1/9y

9(x+2) = y

The inverse function

f^-1(x) = 9(x+2)

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3 years ago

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What is 4/5 divided 1/3

vova2212 [387]

The answer would be 2.4, or in fraction form 12/5. Please mark brainliest <3

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3 years ago

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An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the

MrRa [10]

your question is incomplete, here you can find the complete question below:

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.

a. if the terminal ray of the angle passes through the point(3.38,2.32), whta is the slope of the terminal ray of the angle?

b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?

c. if the terminal ray of the angle passes through the point(1.1,3.95), what is the slope of the terminal ray of the angle?

Answer:

a. 1.45

b. 2.56

c. 3.59

Step-by-step explanation:

As we know that formula to find the slope is change in y-coordinates divided by change in x-coordinates.

$slope=\frac{chnage\ in\ y}{chnage\ in\ x}=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

It is given that initial point is (x1,y1)=(0,0)

Part(a)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(3.38,2.32)

so the slope of the terminal ray is

$slope=\frac{3.38-0}{2.32-0}=\frac{3.38}{2.32}= 1.45$

Part(b)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.49,3.82)

so the slope of the terminal ray is

$slope=\frac{3.82-0}{1.49-0}=\frac{3.82}{1.49}=2.56$

Part(c)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.1,3.95)

so the slope of the terminal ray is

$slpoe=\frac{3.95-0}{1.1-0}=\frac{3.95}{1.1}= 3.59$

6 0

3 years ago

Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =

Helen [10]

For the ODE

$ty'+2y=\sin t$

multiply both sides by t so that the left side can be condensed into the derivative of a product:

$t^2y'+2ty=t\sin t$

$\implies(t^2y)'=t\sin t$

Integrate both sides with respect to t :

$t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C$

Divide both sides by $t^2$ to solve for y :

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}$

Now use the initial condition to solve for C :

$y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}$

$\implies9=\dfrac4{\pi^2}(1+C)$

$\implies C=\dfrac{9\pi^2}4-1$

So the particular solution to the IVP is

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}$

$y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}$

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3 years ago

Español Use the equation below to find y, if m=4, x=8, and b=12. y=mx-b

Novay_Z [31]

Answer

$y=4* 8 -12\\$

Step-by-step explanation:

4 x 8 = 32

y=32-12

y=20

3 0

2 years ago