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Gwar [14]
2 years ago
9

Definition of property change.chemistry ​

Chemistry
1 answer:
Black_prince [1.1K]2 years ago
7 0

Answer:

This is the change of one type of matter into another type of matter

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If you want 1,775 mL of 48 M MgCl2 solution, how many grams of MgCl2 do you need?
vlada-n [284]

Answer:

0.1

Explanation:

3 0
3 years ago
The change in velocity over a specific amount of time Includes speeding up. slowing down or changing direction. This is known as
Nana76 [90]

Answer:

Acceleration

Explanation:

Acceleration = \frac{velocity}{time}

3 0
3 years ago
1) What happens when the pressure above the surface of a liquid is equal to the vapor
xenn [34]

When the atmospheric pressure is equal to the vapor pressure of the liquid, boiling of liquid will begin.

<h3>What happens when atmospheric pressure is equal to the vapor pressure of liquid?</h3>

When the atmospheric pressure is equal to the vapor pressure of the liquid, boiling will begin. The bubbles formation started to the liquid molecules which have gained enough energy to change to the gaseous phase.

The vapor pressure of ethanol is 5.95 kPa at 20.0 °C, and its vapor pressure is 53.3 kPa at 63.5 °C.

Learn more about pressure here: brainly.com/question/25965960

7 0
2 years ago
Calculate the density of chloroform
Rina8888 [55]

Answer: The density of chloroform is 1.47 g/mL

Explanation : Given,

Volume = 40.5 mL

Mass of cylinder = 85.16 g

Mass of cylinder and liquid = 145.10 g

First we have to calculate the mass of liquid (chloroform).

Mass of liquid = Mass of cylinder and liquid - Mass of cylinder

Mass of liquid = 145.10 g - 85.6 g

Mass of liquid = 59.5 g

Now we have to calculate the density of liquid (chloroform).

Formula used:

Density=\frac{Mass}{Volume}

Now putting g all the given values in this formula, we get:

Density=\frac{59.5g}{40.5mL}

Density=1.47g/mL

Therefore, the density of chloroform is 1.47 g/mL

5 0
3 years ago
Given the following UNBALANCED reaction: NH3 (g) &lt;--&gt; N2 (g) + H2 (g) If 1
Yakvenalex [24]

Answer:

C. 1.35

Explanation:

                                                     2NH3 (g) <-->          N2 (g) +             3H2 (g)

Initial concentration                2.2 mol/0.95L       1.1 mol/0.95L           0

change in concentration        2x                             x                           3x

                                                 -0.84 M                  +0.42M                +1.26M

Equilibrium                       1.4 mol/0.95L=1.47M        1.58 M                   1.26 M

concentration

Change in concentration(NH3) = (2.2-1.4)mol/0.95 L = 0.84M

Equilibrium concentration (N2) = 1.1/0.95 +0.42=1.58 M

Equilibrium concentration(NH3) = 1.4/0.95 = 1.47M

K = [N2]*{H2]/[NH3] = 1.58M*1.26M/1.47M = 1.35 M

8 0
3 years ago
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