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Anon25 [30]
3 years ago
14

Is oil not mixing with water a physical or chemical change

Chemistry
1 answer:
Lorico [155]3 years ago
6 0
Physical change, it is because no new substances are formed
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3 years ago
Classify each item by matching as organic
Aloiza [94]
<span>Table salt is inorganic TNT is organic Glucose is organic 2,4-D is organic Limestone is inorganic Water is inorganic What makes a compound organic is the presence of a carbon, with the exception of cabonates. In this case all of the compounds in this list that have carbon except for CaCO3, are organic and the other compounds are inorganic.</span>
3 0
3 years ago
Given the two reactions H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.57×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.46×10−19, what is the equilib
Dvinal [7]

<u>Answer:</u> The value of K_c for the final reaction is 7.16\times 10^{25}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  H_2S(aq.)\rightleftharpoons HS^-(aq.)+H^(aq.);K_1

<u>Equation 2:</u>  HS^-(aq.)\rightleftharpoons S^{2-}(aq.)+H^(aq.);K_2

The net equation follows:

S^{2-}(aq.)+2H^+(aq.)\rightleftharpoons H_2S(aq.);K_c

As, the net reaction is the result of the addition of reverse of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of inverse of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=\frac{1}{K_1}\times \frac{1}{K_2}

We are given:

K_1=9.57\times 10^{-8}

K_2=1.46\times 10^{-19}

Putting values in above equation, we get:

K_c=\frac{1}{(9.57\times 10^{-8})}\times \frac{1}{(1.46\times 10^{-19})}=7.16\times 10^{25}

Hence, the value of K_c for the final reaction is 7.16\times 10^{25}

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3 years ago
Suppose you mix 12.8 g of one substance with 11.4 g of another. The picture shows the mass you measure for the mixture. Is this
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Explanation: simple

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3 years ago
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Lera25 [3.4K]

Answer:

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8 0
3 years ago
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