Question

Calculate the amount of energy released when 2,064 g of water are cooled from 92 ˚C to 45˚C. The specific heat of water is 4.184.

Answer 1

Answer: Q= - 405,881 J or -405.88 kJ

Explanation: To find the amount of heat released we will use the formula of heat which is Q = mc∆T.

Q= 2,064 g ( 4.184 J/g°C) ( 45°C -92°C)

= 2,064 g ( 4.184 J/g°C) ( -47°C)

= -405,881 J

Or we can convert this into kJ which is equal to -405.88 kJ.