125 Each half life it divides by 2 the amount
1000/2=500
500/2=250
250/2=125
Answer:
The concentration of cyclobutane after 875 seconds is approximately 0.000961 M
Explanation:
The initial concentration of cyclobutane, C₄H₈, [A₀] = 0.00150 M
The final concentration of cyclobutane, [] = 0.00119 M
The time for the reaction, t = 455 seconds
Therefore, the Rate Law for the first order reaction is presented as follows;
Therefore, we get;
Which gives;
k ≈ 5.088 × 10⁻⁴ s⁻¹
The concentration after 875 seconds is given as follows;
[] = [A₀]·
Therefore;
[] = 0.00150 × = 0.000961
The concentration of cyclobutane after 875 seconds, [] ≈ 0.000961 M
706000 in scientific notation is 7.06x10^5
Number of states present in each band will be equal to total of all the states contributed by N atoms.
For instance, s band will contain N states.
Similarly, a p band will contain 3N states.