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FinnZ [79.3K]
3 years ago
6

Calculate the amount of energy released when 2,064 g of water are cooled from 92 ˚C to 45˚C. The specific heat of water is 4.184

.
Chemistry
1 answer:
Andrews [41]3 years ago
8 0

Answer: Q= - 405,881 J or -405.88 kJ

Explanation: To find the amount of heat released we will use the formula of heat which is Q = mc∆T.

Q= 2,064 g ( 4.184 J/g°C) ( 45°C -92°C)

= 2,064 g ( 4.184 J/g°C) ( -47°C)

= -405,881 J

Or we can convert this into kJ which is equal to -405.88 kJ.

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How many km are in 5.6mm? 5.6x103 5.6x10-6 5.6x10-3 5.6x106​
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Hey there :)

<em>Q</em><em>u</em><em>e</em><em>s</em><em>t</em><em>i</em><em>o</em><em>n</em><em>:</em><em> </em><em>How many km are in 5.6mm? </em>

<em>=</em><em>></em><em>5.6x10</em><em>^</em><em>3 </em>

<em>=</em><em>></em><em>5.6x10</em><em>^</em><em>-6 </em>

<em>=</em><em>></em><em>5.6x10</em><em>^</em><em>-3 </em>

<em>=</em><em>></em><em> </em><em>5.6x10</em><em>^</em><em>6</em>

<em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em><em>-</em>

5.6 \times 10^{ - 6}

<em>E</em><em>x</em><em>p</em><em>l</em><em>a</em><em>n</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em>:</em><em>-</em>

By using the formula-

1millimeter =  \frac{1}{1000000}

As 1 with 6 zeros, we convert it into exponential form.

=  >  \frac{1}{10^{6} }

As this above value is fraction type, we can do the reciprocal, thus, the exponent gets a negative value.

=  > 10^{ - 6}

Now combine with given question.

=  > 5.6 \times 10^{ - 6}

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