Answer:
False
Step-by-step explanation:
If the value is a root of the polynomial, then the remainder will be 0. This means that the root as a factor will multiply to make the polynomial.
Answer:
see below
Step-by-step explanation:
The formula for the sum of an infinite geometric series with first term a1 and common ratio r (where |r| < 1) is ...
sum = a1/(1 -r)
Applying this to the given series, we get ...
a. sum = 5/(1 -3/4) = 5/(1/4) = 20
b. sum = d/(1 -1/t) = d/((t-1)/t) = dt/(t-1)
_____
The derivation of the above formula is in most texts on sequences and series. In general, you write an expression for the difference of the sum (S) and the product r·S. You find all terms of the series cancel except the first and last, and the last goes to zero in the limit, because r^∞ → 0 for |r| < 1. Hence you get ...
S -rS = a1
S = a1/(1 -r)
I assume you meant 
.
Reflecting across the x-axis would give 
.
Reflecting across the y-axis would give 
.
Answer: 9 kilos total thats it
Step-by-step explanation: Leaving the store Fatima thinks,“Each bag of groceries seems asheavy as a watermelon!”UseFatima’s idea about theweight of thewatermelon to estimate the total weight of 7 bags.c.The grocer helps carry about 9 kilograms. Fatima carries the rest.Estimate how many kilograms ofgroceries Fatima carries.d.It takes Fatima 12 minutes to drive to the bank after she leaves the store and then 34 more minutesto drive home.How many minutes does Fatima drive after she leaves the store?
Answer:
1) y = (x + 8)² + 7; 5) y = (x - 6)² + 10; 7) y = (x - 3)² - 4
Step-by-step explanation:
Complete the square in order to figure these out. To complete the square, use the formula <em>[½B]</em><em>²</em><em>.</em><em> </em>Each time you do this, you get a perfect trinomial in the form of a product of two monomials [<em>h</em>], then you have to figure out how much more to deduct from or add on to your <em>C</em><em> </em>they gave you in each exercise [<em>k</em>].
If you are still in need of assistance, do not hesitate to let me know and subscribe to my channel [username: MATHEMATICS WIZARD].
I am joyous to assist you anytime.
