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bearhunter [10]
1 year ago
12

You have a version control system installed. Several developers work with this system. A new developer wants to work on the code

. What is the first task that the developer must perform
Computers and Technology
1 answer:
telo118 [61]1 year ago
5 0

The first task that the developer must perform is to check out the existing code. A code developer can develop software and applications.

<h3>What is a code developer?</h3>

A code developer, also known as a computer programmer or software developer, is a person that works by developing new software and applications.

Code developers write and also test computer codes in order to determine if they function in a proper manner.

Code developers play a fundamental role in the industry by developing instructions that computers can easily follow.

Learn more about software development here:

brainly.com/question/26135704

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Assign testResult with 1 if either geneticMarkerA is 1 or geneticMarkerB is 1. If geneticMarkerA and geneticMarkerB are both 1,
OverLord2011 [107]

Answer:

Following python statement will give the assignment to testResult as specified:

if((geneticMarkerA == 1) or (geneticMarkerB ==1)):

   testResult = 1

if((geneticMarkerA ==1) and (geneticMarkerB == 1)):

   testResult = 0

if((geneticMarkerA == 0) and (geneticMarkerB == 0)):

   testResult = 0

Explanation:

In above statements or and and operator are used to check the conditions of set of values present in variable geneticMarkerA and geneticMarkerB.

Based on if the condition evaluate to true or false respective values to testResult varaible is assigned.

Following is sample run for above statements:

geneticMarkerA = 1

geneticMarkerB = 0

if((geneticMarkerA == 1) or (geneticMarkerB ==1)):

   testResult = 1

if((geneticMarkerA ==1) and (geneticMarkerB == 1)):

   testResult = 0

if((geneticMarkerA == 0) and (geneticMarkerB == 0)):

   testResult = 0

print(testResult)

Output

1

4 0
3 years ago
If you are feeling fatigued or sleepy while driving _________________.
vlada-n [284]
The best awnser is D but A is also doable
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3 years ago
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Please Help!<br><br>in return brainliest and special thanks
arlik [135]
1. Option 3
2. Option 2
3. Option 3
8 0
3 years ago
The ___________ method returns the length of an array.
MaRussiya [10]

Answer:

A. Append

Explanation:

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2 years ago
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Computer system with a 32-bit logical address and 4k-byte page size. assume that each entry of a page table consists of 4bytes.
Annette [7]

The number of bits in the physical address is 26 bits. The number of entries in a page table is \mathbf{2^{20}} entries. The size of the page table in a one-level paging scheme is 4MB.

<h3>
What is paging in Operating System?</h3>

Paging is a storage method used in operating systems to recover activities as pages from secondary storage and place them in primary memory. The basic purpose of pagination is to separate each procedure into pages.

We are given the following parameters:

  • 32-bit logical address
  • Page size = 4 KB = \mathbf{2^{12} \ bytes }
  • Size of each Page table entry = 4 bytes

Suppose the system supports physical memory size = 64 MB = \mathbf{2^{26} \ bytes}

Thus, the number of bits in the physical address is computed as:

= \mathbf{log_2 \{Physical-memory-size\}}

=\mathbf{log_2(2^{26})}}

= 26 bits

The number of entries in a page table = logical address space size/page size

The number of entries in a page table \mathbf{= \dfrac{2^{32}}{2^{12}}}

\mathbf{=2^{20}} entries

In a one-level paging scheme, the size of the table is:

= entire no. of page entries × page table size

= \mathbf{2^{20}\times 4 \ bytes}

= 4 MB

b.

suppose that this system supports up to 2^30 bytes of physical memory.

  • The size of the page table will be the same as 4 MB due to the fact that the number of entries, as well as, the page table entry size is the same.

Since the size of the page table surpasses that of a single page. A page cannot include a whole page table. Therefore, the page table must be broken into parts to fit onto numerous pages, and an additional level of the page table is required to access this page table.

  • This is called the Multi-Level Paging system.

Therefore, we can conclude that the number of bits in the physical address is 26 bits, the number of entries in a page table is \mathbf{2^{20}} entries, and the size of the page table in a one-level paging scheme is 4MB.

Learn more about Paging in Operating System here:

brainly.com/question/17004314

#SPJ1

4 0
1 year ago
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