If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
Answer:
Step-by-step explanation: multiply 4 by 12 then 4 by 3 then 4 by 9.
Answer:
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Step-by-step explanation:
Answer: positive
Step-by-step explanation:
Answer:
Step-by-step explanation:
I can not see your answers to choose but with this equation for 2 variables, you can replace the values of x and y and see if that is right or not.
For example, to know (-2,5) is a solution, you replace x= -2 and y= 5
into this equation: -3x -y = 6
and you have: -3*(-2) -5 =6
or 6-5 =6, and you find that is impossible, so (-2.5) is not a solution.
Hope you understand it
