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valentina_108 [34]
3 years ago
10

What is the quotient of 840 divided by 28 with a remainder?

Mathematics
2 answers:
kondaur [170]3 years ago
7 0

Answer:

840 28 = 30

30 = 300 to the nearest tenth

30 = 30 to the nearest hundredth

30 = 30 to the nearest thousandth

= 0 to the nearest tenth

= 0 to the nearest hundredth

= 0 to the nearest thousandth

Other Divisions Math homework are

840 divide by half plus 20

Step-by-step explanation:

slava [35]3 years ago
3 0

Answer:

30

Step-by-step explanation:

There is no remainder. You can do 84/28, which is 3, but since it is tens place, 30. You can not divide 0 to 28, so it is 0. 30+0=30

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Consider the following function:y=1/(x+5)+2
Galina-37 [17]

Answer:

Step-by-step explanation:

Starting with the parent function, x was replaced by (x + 5), indicating that the graph of the new function is that of the old function shifted 5 units to the LEFT.  That +2 shifts this result UP by 2 units.

8 0
3 years ago
Read 2 more answers
24 POINTS PLEASE
Alenkasestr [34]

Answer:

2.5X=1.0 try this i think

Step-by-step explanation:

tRY THAT

4 0
3 years ago
Ivy is running errands for her mother. She bikes along straight paths to the supermarket, the bank, and then back home.Find the
chubhunter [2.5K]

The distance between Ivy's house and the supermarket and the distance between the supermarket and the bank:
H&S = 1,014 M; and S&B = 854m. This is resolved using the Sine Theorem.

<h3>What is the calculation backing the above solution?</h3>

Notice that the Angles of a Triangle add up to 180° That is

∠A + ∠B  + ∠C = 180°

Thus,

∠C = 180° - 32° - 109°

= 39°

Recall the Sine Theorem which indicates;

a/SinA = b/SinB = c/SinC

thus given that

AC = 1,523m

We have

AC/SinB = BC/SinA


BC = AC/SinB * SinA

= 1523/Sin109° * Sin32°

BC =854m

Therefore

AC/SinB = AB/SinC
Thus,

AB = AC/SinB * SinC

= 1523/Sin109° * Sin39°
AB ≈ 1,014m

Learn more about the Sine Theorem at;
brainly.com/question/27174058
#SPJ1

5 0
2 years ago
Find the length of line segment UV.
pshichka [43]

Answer:

The length of the line segment UV is 76 units

Step-by-step explanation:

In a triangle, the line segment joining the mid-points of two sides is parallel to the third side and equal to half its length

In Δ ONT

∵ U is the mid-point of ON

∵ V is the mid-point of TN

→ That means UV is joining the mid-points of two sides

∴ UV // OT

∴ UV = \frac{1}{2} OT

∵ UV = 7x - 8

∵ OT = 12x + 8

∴ 7x - 8 = \frac{1}{2} (12x + 8)

→ Multiply the bracket by \frac{1}{2}

∵ \frac{1}{2} (12x + 8) =  \frac{1}{2} (12x) +  \frac{1}{2} (8) = 6x + 4

∴ 7x - 8 = 6x + 4

→ Add 8 to both sides

∴ 7x - 8 + 8 = 6x + 4 + 8

∴ 7x = 6x + 12

→ Subtract 6x from both sides

∴ 7x - 6x = 6x - 6x + 12

∴ x = 12

→ Substitute the value of x in the expression of UV to find it

∵ UV = 7(12) - 8 = 84 - 8

∴ UV = 76

∴ The length of the line segment UV is 76 units

8 0
3 years ago
Y = 5x - 10 (solve for x)
worty [1.4K]

Answer:

(y+10)/5

Step-by-step explanation:

You start off by adding 10 on both sides cancelling the 10 on the right side and you get y+10=5x. From there you then divide by 5 on both sides and you get your answer of (y+10)/5.

4 0
3 years ago
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