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Zarrin [17]
2 years ago
14

Can anyone help me??? PLZ….

Mathematics
1 answer:
bezimeni [28]2 years ago
4 0
7. Obtuse
8. Acute
9. No, because it’s the hypotenuse
10. Yes, because that part is not the hypotenuse and it is less than the greatest angle
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Simplify the expression. 6(7n – 5m) + 8m
borishaifa [10]
6(7n – 5m) + 8m
42n - 30m + 8m
42n -22m
Answer: 42n-22m

7 0
3 years ago
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Adrianna can read 7 pages in 10 minutes. At this rate,how many pages can she read in 25 minutes
Westkost [7]

Use a proportion. 7/10 = x/25. Multiply 10 by 2.5 to get 25. Similarly, multiply 7 by 2.5 to get 17.5. 17 1/2 pages.

5 0
3 years ago
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For integers a, b and k, we know that a >12, b > 20 and a < b. If b=7k, what is the value of k ?
Doss [256]

This question is incomplete, the complete question is;

For integers a, b and k, we know that a > 12, b < 20 and a < b. If b=7k, what is the value of k ?

Answer: the value of k = 2

Step-by-step explanation:

Given that;

a > 12

b < 20

a < b

If b = 7k

Now if k = 1      {b = 7k = 7}

b would be equal to 7 but b has to be greater than 20

IT CANT BE

if k = 2        { b = 7k = 14}

b would be equal to 14, a is greater than 12, b has to be less than b; 14 < 20,

a has to be less than than b ( 12 < 14 )

IT IS

if k = 3      {b = 7k = 21}  

b would be equal to 21, so b is greater than 20 and a is less than 21

IT CANT BE

Therefore the value of k = 2

5 0
3 years ago
A pizza pan is removed at 9:00 PM from an oven whose temperature is fixed at 450°F into a room that is a constant 70°F. After 5​
gladu [14]

Answer:

A) It will get to a temperature of 125°F at 9:19 PM

B) It will get to a temperature of 150°F at 9:16 PM

C) as time passes temperature approaches the initial temperature of 450°F

Step-by-step explanation:

We are given;

Initial temperature; T_i = 450°F

Room temperature; T_r = 70°F

From Newton's law of cooling, temperature after time (t) is given as;

T(t) = T_r + (T_i - T_r)e^(-kt)

Where k is cooling rate and t is time after the initial temperature.

Now, we are told that After 5​ minutes, the temperature is 300°F.

Thus;

300 = 70 + (450 - 70)e^(-5k)

300 - 70 = 380e^(-5k)

230/380 = e^(-5k)

e^(-5k) = 0.6053

-5k = In 0.6053

-5k = -0.502

k = 0.502/5

k = 0.1004 /min

A) Thus, at temperature of 125°F, we can find the time from;

125 = 70 + (450 - 70)e^(-0.1004t)

125 - 70 = 380e^(-0.1004t)

55/380 = e^(-0.1004t)

In (55/380) = -0.1004t

-0.1004t = -1.9328

t = 1.9328/0.1018

t ≈ 19 minutes

Thus, it will get to a temperature of 125°F at 9:19 PM

B) Thus, at temperature of 150°F, we can find the time from;

150 = 70 + (450 - 70)e^(-0.1004t)

150 - 70 = 380e^(-0.1004t)

80/380 = e^(-0.1004t)

In (80/380) = -0.1004t

-0.1004t = -1.5581

t = 1.5581/0.1004

t ≈ 16 minutes.

Thus, it will get to a temperature of 150°F at 9:16 PM

C) As time passes which means as it approaches to infinity, it means that e^(-kt) gets to 1.

Thus,we have;

T(t) = T_r + (T_i - T_r)

T_r will cancel out to give;

T(t) = T_i

Thus, as time passes temperature approaches the initial temperature of 450°F

6 0
2 years ago
The value of y varies directly with c. If x = 2, then y = 7. Find the value of x if y = 84.​
shtirl [24]

Answer:

x=24

Step-by-step explanation:

y = x*c

x=2, y=7

2*c=7 => c=7/2

x*7/2 = 84

x = 84*2/7

x = 12*2

x = 24

3 0
3 years ago
Read 2 more answers
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