The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant = 
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
Answer:
2
Step-by-step explanation:
The tangent is positive in quadrants I and III. There are two angles with that tangent value:
33.96° and 213.69°
1. 10x+6=8-2(x+6)
2. 10x+6=6(x+6)
(distribute the 6)
3. 10x+6=6x+36
(Move the 6x to the other side by subtracting)
4. 4x+6=36
(Move the 6 to the other side by subtracting)
5. 4x=30
(divide)
x=7.5
Hope this helped! :)
Answer:
No Solution
Step-by-step explanation:
12x + 3 = 72x + 5
subtract 12x from both sides
end up with
3 = 72x - 12x + 5
subtract 12x to 72x
3 = 60x + 5
-5 from both sides
-8 = 60x
since x is a bigger number the answer would be NO SOLUTION
12x + 3 = 72x + 5
I do not understand lins logic
x + 6 = 7x + 10
subtract 6 from both sides
x = 7x + 4
move 7x to the other side
7x = 4
divide 7
x = 0.5
Also wrong because I get how lin got that answer
My way
12x + 3 = 72x + 5
-12 x from both sides
3 = 60x + 5
+5 to other side
8 = 60x
if the x was on the other side it would make sense
but it is not so the Answer is NO SOLUTION
Hope this Helped :)
Y -Y1 = m(x-x1)
D. Y-9 = 2(x+3)
