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zalisa [80]
3 years ago
8

The distribution of SAT scores is normal with a mean of µ = 500 and a standard deviation of σ = 100. a. What SAT score (i.e., X

score) separates the top 15% of the distribution from the rest?b. What SAT score (i.e., X score) separates the top 10% of the distribution from the rest?c. What SAT score (i.e., X score) separates the top 2% of the distribution from the rest?
Mathematics
1 answer:
I am Lyosha [343]3 years ago
4 0

Answer:

a) 604

b) 628

c) 705.5

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 500, \sigma = 100

a. What SAT score (i.e., X score) separates the top 15% of the distribution from the rest?

This is the value of X when Z has a pvalue of 0.85. So it is X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 500}{100}

X - 500 = 100*1.04

X = 604

b. What SAT score (i.e., X score) separates the top 10% of the distribution from the rest?

This is the value of X when Z has a pvalue of 0.90. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 500}{100}

X - 500 = 100*1.28

X = 628

c. What SAT score (i.e., X score) separates the top 2% of the distribution from the rest?

This is the value of X when Z has a pvalue of 0.98.So it is X when Z = 2.055.

Z = \frac{X - \mu}{\sigma}

2.055 = \frac{X - 500}{100}

X - 500 = 100*2.055

X = 705.5

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