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Eva8 [605]
2 years ago
12

Y=-2/3x+3 in standard form

Mathematics
1 answer:
Luba_88 [7]2 years ago
6 0

Answer:

-2/3x + 3

Step-by-step explanation:

Standard form is just ax^2 + bx + c

In this equation, there is no ax^2. So we have 2/3x + 3.

We don't have to make any changes because the equation is already in standard form.

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-125p^{12}64^{18}u^{3}
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What is the surface area of a rectangular prism. 8yd in length , 5yd in height , and 2yd in width.
irakobra [83]
100 yd ^2
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7 0
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Please help me please ​
Lubov Fominskaja [6]

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(x+4)+(2x)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Drag the expressions into the boxes to correctly complete the table. Polynomial Not a polynomial
uranmaximum [27]

The answer to the given question is as below:-

Polynomials:-

x³-7x²+9x-5x⁴-20

x⁵-5x⁴+4x³+2x-1

3x²-5x⁴+2x-12

Non-polynomial:-

x⁻5-5x⁻⁴+4x⁻³+2x⁻1-1

\dfrac{4}{x^4}+ \dfrac{3}{x^3}-\dfrac{2}{x^4}-1

\sqrt[4]{x} -\sqrt[3]{x} 4+\sqrt{x}-8x+16

<h3>What are polynomials?</h3>

A polynomial is a mathematical equation made up of indeterminates and coefficients and involves only addition, subtraction, multiplication, and non-negative integer exponentiation of variables. The exponents of the polynomials can not be irrational.

So the table will be formed as:-

Polynomials:-                            Non-polynomial:-        

x³-7x²+9x-5x⁴-20                     x⁻5-5x⁻⁴+4x⁻³+2x⁻1-1        

x⁵-5x⁴+4x³+2x-1                        \dfrac{4}{x^4}+ \dfrac{3}{x^3}-\dfrac{2}{x^4}-1

3x²-5x⁴+2x-12                           \sqrt[4]{x} -\sqrt[3]{x} 4+\sqrt{x}-8x+16

Therefore the polynomials and non-polynomials are shown in the table above.

To know more about polynomials follow

brainly.com/question/2833285

#SPJ1

5 0
2 years ago
Three plus the reciprocal of a number equals 7 divided by that number. What is the number?
tester [92]
3+1/x *x = 7/x*x
3x+1 = 7
3x+1-1=7-1
3x=6
3x/3 =6/3
x =2


3 0
4 years ago
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