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lys-0071 [83]
3 years ago
12

Four years after a tree was planted, its height was 6 feet. Eight years after it was planted, its height was 8 feet. How tall wi

ll the tree be ten years after it was planted?
Mathematics
2 answers:
german3 years ago
4 0

Answer:

It will be 10 feet after 10 years

Naya [18.7K]3 years ago
4 0

Answer:

I am not that sure but it could be 8 ft. 10 ft. or 12.ft

Step-by-step explanation:

Hope It Helps!

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Find the unit rate please and thank you...
Gnom [1K]

Answer:

the unit rate is 1/10.

Step-by-step explanation:

4/40 divided by 4 equals 1/10

8 0
3 years ago
Read 2 more answers
Can someone help me with this two problems?
ANEK [815]

2x+4y=0

substitute y with 0

2x+4(0)=0

solve the equation

2x+0=0

2x=0

divide by 2 on both sides

x=0

4x+8y=7

substitute y with 0

4x+8(0)=7

solve the equation

4x+0=7

4x=7

divide by 4 on both sides

x=7/4 or x=1 3/4 or x=1.75

3x-7y=-29

2x+2y=6

solve the bottom equation

3x-7y=-29

x=3-y

substitute for x

3(3-y)-7y=-29

solve the equation

y=19/5

now substitute for y

x=3-\frac{19}{5}

solve for x

x=-4/5

the possible solution of the system is the ordered pair

(x,y)=(-\frac{4}{5} ,\frac{19}{5})

3 0
4 years ago
Sadie types 800 words in 16 minutes. What is the unit rate in words per minute?
anyanavicka [17]

Answer:

50 worlds per minute

Step-by-step explanation:

800/16=50

7 0
3 years ago
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How many lines of symmetry does a regular octagon have?
Lesechka [4]

Answer:

8

Step-by-step explanation:

  • An Equilateral Triangle (3 sides) has 3 Lines of Symmetry
  • A Regular Pentagon (5 sides) has 5 Lines of Symmetry
  • A Regular Hexagon (6 sides) has 6 Lines of Symmetry
  • A Regular Heptagon (7 sides) has 7 Lines of Symmetry
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7 0
3 years ago
Match the information on the left with the appropriate equation on the right.
solmaris [256]

Answer:

Step-by-step explanation:

1). Equation of a line which has slope 'm' and y-intercept as 'b' is,

y = mx + b

If slope 'm' = 1 and y-intercept 'b' = -3

Equation of the line will be,

y = x - 3

x - y = 3

2). Equation of a line having slope 'm' and passing through a point (x', y') is,

y - y' = m(x - x')

If the slope 'm' = 1 and point is (-1, 2),

The the equation of the line will be,

y - 2 = 1(x + 1)

y = x + 1 + 2

y = x + 3

x - y = -3

3). Equation of a line passing through two points (x_1, y_1) and (x_2,y_2) will be,

y-y_1=\frac{(y_2-y_1)}{(x_2-x_1)}(x-x_1)

If this line passes through (-2, 3) and (-3, 4),

y-3=\frac{(4-3)}{(-3+2)}(x+2)

y - 3 = -1(x + 2)

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y = -x + 1

x + y = 1

4 0
3 years ago
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