Answer:
RL=5x+28 and
RO=8X-11
diagonal of square bisect equally the side
:.5x+28=8x-11
11+28=8x-5x
39=3x
x=39/3=13
<u>RY</u><u>=</u><u>RL</u><u>=</u><u>5</u><u>x</u><u>+</u><u>2</u><u>8</u><u>=</u><u>5</u><u>×</u><u>1</u><u>3</u><u>+</u><u>2</u><u>8</u><u>=</u><u>9</u><u>3</u><u>If the answer is 93, move to </u><u>answer</u><u>.</u>
Answer:
(4,0) and (- 2,0): Answer
Step-by-step explanation:
Absolute value questions have two essential steps.
1. Solve the equation as it is written.
2. Solve it changing the sign of the right hand side. I will include a graph to confirm my answer
4*abs(x - 1) = 12 Divide by 4
- abs(x - 1) = 12/4
- abs(x - 1) = 3 Equate this to 3
- x - 1 = 3 Add 1 to both sides
- x - 1 + 1 = 3 + 1 Combine
- x = 4
4*abs(x - 1) = - 12 Divide by 4
- abs(x - 1) = - 12/4
- abs(x - 1) = - 3
- x - 1 = - 3 Add 1 to both sides
- x - 1 + 1 = -3 + 1
- x = - 2
So this has 2 answers
(4,0) and (- 2,0)
The answer should be A 160
Answer:
Step-by-step explanation:
4). Given sequence → 3, 5, 7, 9, 11........
Common difference of an arithmetic sequence is defined by,
Common difference = Successive term - previous term
= 2nd term - 1st term
= 5 - 3
= 2
5). Given sequence → 16, 19, 22, 25........
Common difference of an arithmetic sequence = Second term - first term
= 19 - 16
= 3
Find the distance between the points t(13, 1.6)t(13, 1.6) and v(5.4, 3.7)v(5.4, 3.7).
1
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The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:
Thus the distance between points t(13, 1.6) and v(5.4, 3.7) is found using the formula as:
