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Pavlova-9 [17]
2 years ago
8

The coordinates of points A, B, and C are (5, 4), (–2, 1), and (4, –4), respectively. Which point, B or C, is closer to point A?

Mathematics
2 answers:
Elena-2011 [213]2 years ago
6 0

Answer:

The distance between two points (x1,y1) and (x2,y2) = √((x1-x2)2+(y1-y2)2) Distance between A and B = √((5--2)2+(4-1)2) = √(72+32) = √(49+9) = √58 = 7.62 Distance between A and C = √(12+82) = √65 = 8.06 Point B is closer to A. Another method to solve this problem is to draw the points on a graph paper and measure distance with a ruler.

Katarina [22]2 years ago
4 0

Answer:

B

Step-by-step explanation:

|AB|=\sqrt{(1-4)^{2}+(-2-5)^2 }=\sqrt{58}

|AC|=\sqrt{(-4-4)^{2}+(4-5)^2 }=\sqrt{65}

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Digiron [165]

Answer:

cost of paint set = $ 13.64

cost of sketch book = $ 6.82

cost of brush = $ 4.55

Step-by-step explanation:

Let the cost of paint set is s.

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cost of brush = s/3

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3 years ago
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Limit of x^2-81/x+9<br> As x goes toward -9
Semmy [17]
Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

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Simplity x + 9

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Now replace x = -9

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_______________

The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18




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Answer: whats the question?

Step-by-step explanation:

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vovangra [49]

Answer:

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Step-by-step explanation:

We can use the Pythagorean theorem

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